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Theorem 2.31 proof — Hermitian witness for Kraus-product dependence

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WatrousTQI.kraus_dependence_hermitian_witness

by Mrnaiq · Nov 12, 2026 · Mathlib 0df444a (Lean v4.33.1)

convexitykraus-operatorsprove2quantumquantum-channels

For positive input and output dimensions and a nonempty finite family A0,…,Am−1A_0,\ldots,A_{m-1}A0​,…,Am−1​ of rectangular complex matrices, complex linear dependence of the indexed family (Ab†Aa)a,b(A_b^\dagger A_a)_{a,b}(Ab†​Aa​)a,b​ yields a nonzero Hermitian coefficient matrix:

∃H=H†≠0:∑a,bHabAb†Aa=0.\exists H=H^\dagger\ne0:\quad\sum_{a,b}H_{ab}A_b^\dagger A_a=0.∃H=H†=0:a,b∑​Hab​Ab†​Aa​=0.

This algebraic step does not require channel normalization or independence of the original Kraus operators. It is extracted from equations (2.184)–(2.187), whose argument uses neither condition.

Preamble
import Mathlib
set_option autoImplicit false
noncomputable section
open scoped Matrix ComplexConjugate ComplexOrder BigOperators
Formal statement
namespace WatrousTQI
theorem kraus_dependence_hermitian_witness {dx dy m : ℕ}
    (hdx : 0 < dx) (hdy : 0 < dy) (hm : 0 < m)
    (A : Fin m → Matrix (Fin dy) (Fin dx) ℂ)
    (hdep : ¬ LinearIndependent ℂ (fun ab : Fin m × Fin m => (A ab.2)ᴴ * A ab.1)) :
    ∃ H : Matrix (Fin m) (Fin m) ℂ,
      H.IsHermitian ∧ H ≠ 0 ∧ ∑ a, ∑ b, H a b • ((A b)ᴴ * A a) = 0 := by sorry
end WatrousTQI
Source
John Watrous, The Theory of Quantum Information, Cambridge University Press, 2018, Section 2.2.4, printed pp.96–99. https://cs.uwaterloo.ca/~watrous/TQI/TQI.pdf; Proof of Theorem 2.31, equations (2.184)–(2.187), printed p.98.
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What the Lean code literally says, in plain math · GPT-6 (exact model identifier unavailable)

For all positive natural numbers dx,dy,md_x,d_y,mdx​,dy​,m and every family (Aa)a∈{0,…,m−1}(A_a)_{a\in\{0,\ldots,m-1\}}(Aa​)a∈{0,…,m−1}​ of complex dy×dxd_y\times d_xdy​×dx​ matrices, if the family of m2m^2m2 complex dx×dxd_x\times d_xdx​×dx​ matrices (Ab∗Aa)(a,b)∈{0,…,m−1}2(A_b^*A_a)_{(a,b)\in\{0,\ldots,m-1\}^2}(Ab∗​Aa​)(a,b)∈{0,…,m−1}2​ is not linearly independent over C\mathbb CC, then there exists a complex m×mm\times mm×m matrix HHH such that H=H∗H=H^*H=H∗, H≠0H\ne0H=0, and ∑a=0m−1∑b=0m−1Hab(Ab∗Aa)=0\sum_{a=0}^{m-1}\sum_{b=0}^{m-1}H_{ab}(A_b^*A_a)=0∑a=0m−1​∑b=0m−1​Hab​(Ab∗​Aa​)=0. Here a star denotes conjugate transpose, multiplication by HabH_{ab}Hab​ is complex scalar multiplication, and the final zero is the zero dx×dxd_x\times d_xdx​×dx​ matrix. The dependence hypothesis means there is a nonzero complex coefficient array giving a zero linear combination of those ordered-pair-indexed products. The conclusion requires a nonzero Hermitian coefficient array with the same vanishing sum; it imposes no positivity, normalization, or rank condition on HHH or on the AaA_aAa​. All three dimensions are positive, including the permitted value m=1m=1m=1 when its dependence hypothesis holds, and the family may include zero matrices.

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