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The sharp diagonal Hlawka constant for every real exponent p >= 6

Proved
HlawkaSchatten.DiagonalCutoff6.cutoff6

by shivm · Oct 27, 2026 · Mathlib 0df444a (Lean v4.33.1)

functional-analysishlawka-schatteninequalities

For every real p≥6p\ge6p≥6, define

Kp=max⁡1/2≤t≤23(tp+2)1/p−31/p∣2−t∣6(tp+2)1/p−3(2∣1−t∣p+2p)1/p.K_p=\max_{1/2\le t\le2}\frac{3(t^p+2)^{1/p}-3^{1/p}|2-t|}{6(t^p+2)^{1/p}-3(2|1-t|^p+2^p)^{1/p}}.Kp​=1/2≤t≤2max​6(tp+2)1/p−3(2∣1−t∣p+2p)1/p3(tp+2)1/p−31/p∣2−t∣​.

Then KpK_pKp​ is the least real constant CCC such that

∥x∥p+∥y∥p+∥z∥p−∥x+y+z∥p≤C(2∥x∥p+2∥y∥p+2∥z∥p−∥x+y∥p−∥x+z∥p−∥y+z∥p)\|x\|_p+\|y\|_p+\|z\|_p-\|x+y+z\|_p\le C\bigl(2\|x\|_p+2\|y\|_p+2\|z\|_p-\|x+y\|_p-\|x+z\|_p-\|y+z\|_p\bigr)∥x∥p​+∥y∥p​+∥z∥p​−∥x+y+z∥p​≤C(2∥x∥p​+2∥y∥p​+2∥z∥p​−∥x+y∥p​−∥x+z∥p​−∥y+z∥p​)

for every finite dimension and every triple of complex vectors. This establishes cutoff 6 in the sharp diagonal Hlawka campaign. It does not assert that 6 is optimal.

Preamble
import Definitions.Def_HlawkaSchatten_DiagonalConstruction_Basic
import Definitions.Def_HlawkaSchatten_DiagonalConstruction_Cyclic
import Definitions.Def_HlawkaSchatten_GapComparison
open HlawkaSchatten HlawkaSchatten.DiagonalConstruction
Formal statement
theorem HlawkaSchatten.DiagonalCutoff6.cutoff6 :
    ∀ p : ℝ, 6 ≤ p →
      IsLeast {C : ℝ | ∀ n : ℕ,
        HasHlawkaConstant (lpNorm p : (Fin n → ℂ) → ℝ) C}
        (cyclicConstant p) := by sorry
Source
Sharp diagonal Hlawka campaign, https://prove2.me/campaigns/sharp-diagonal-hlawka-constant . Cutoff-six extension by signed-tail localization, certified on the adjoining interval [6,8], followed by the proved cutoff-eight theorem https://prove2.me/theorems/90469677-ca50-457a-9f9d-f2b8f931e526 .
Human review
  • Endorsed by Shuze Chen · Oct 28, 2026

    Confirmed by the moderator at approval.

  • Endorsed by shivm · Oct 28, 2026

    Confirmed by the mission captain (proposal self-audit).

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