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Values in natural units do not depend on the starting system of units

Proved
VaryingConstants.natural_unit_values_independent_of_units

by Lucas · Oct 2, 2026 · Mathlib 0df444a (Lean v4.33.1)

dimensional-analysisfundamental-constantslinear-algebramathematical-physics

Let D∈Rn×dD\in\mathbb R^{n\times d}D∈Rn×d and let e1,…,ede_1,\dots,e_de1​,…,ed​ be constants with det⁡De≠0\det D_e\neq0detDe​=0 (as in the natural-units milestone). Let x∈R>0nx\in\mathbb R^n_{>0}x∈R>0n​ and let r∈R>0dr\in\mathbb R^d_{>0}r∈R>0d​ be any change of units, giving the configuration r⋅xr\cdot xr⋅x. If sss is a system of natural units for xxx and s′s's′ is a system of natural units for r⋅xr\cdot xr⋅x, then

s′⋅(r⋅x)  =  s⋅x.s'\cdot(r\cdot x) \;=\; s\cdot x .s′⋅(r⋅x)=s⋅x.

So the numerical value of every constant expressed in natural units is the same whatever system of units one started from: in natural units all constants are dimensionless numbers.

Preamble
import Mathlib
import Definitions.Def_VaryingConstants_units
Formal statement
namespace VaryingConstants

theorem natural_unit_values_independent_of_units {n d : ℕ} (D : Matrix (Fin n) (Fin d) ℝ)
    (e : Fin d → Fin n) (he : (D.submatrix e id).det ≠ 0)
    (x : Fin n → ℝ) (hx : IsPositive x) (r : Fin d → ℝ) (hr : IsPositive r)
    (s s' : Fin d → ℝ) (hs : IsNaturalUnitsFor D e x s)
    (hs' : IsNaturalUnitsFor D e (unitRescale D r x) s') :
    unitRescale D s' (unitRescale D r x) = unitRescale D s x := by sorry

end VaryingConstants
Source
J.-P. Uzan, "Varying Constants, Gravitation and Cosmology", Living Rev. Relativity 14 (2011) 2, http://www.livingreviews.org/lrr-2011-2, §2.1.1 "Fundamental parameters", p. 17: "Once a set of three independent constants has been chosen as natural units, then all other constants are dimensionless quantities. The values of these combinations of constants does not depend on ... the definition of the units".
Read-back

What the Lean code literally says, in plain math · Aristotle (Harmonic)

Non-blind read-back. This read-back was written by the same agent that drafted the Lean statement, at the explicit request of the proposal owner. It is not an independent, blind audit and must not be treated as independent testimony; the reviewer should compare the Lean code against the source directly.

For all natural numbers n,dn,dn,d, every real n×dn\times dn×d matrix DDD, every e:{0,…,d−1}→{0,…,n−1}e:\{0,\dots,d-1\}\to\{0,\dots,n-1\}e:{0,…,d−1}→{0,…,n−1} with det⁡(De(j),k)j,k≠0\det(D_{e(j),k})_{j,k}\neq0det(De(j),k​)j,k​=0, every x∈Rnx\in\mathbb R^nx∈Rn with all xi>0x_i>0xi​>0, every r∈Rdr\in\mathbb R^dr∈Rd with all rk>0r_k>0rk​>0, and all s,s′∈Rds,s'\in\mathbb R^ds,s′∈Rd such that (a) all sk>0s_k>0sk​>0 and xe(j)∏kskDe(j),k=1x_{e(j)}\prod_k s_k^{D_{e(j),k}}=1xe(j)​∏k​skDe(j),k​​=1 for every jjj, and (b) all sk′>0s'_k>0sk′​>0 and ye(j)∏k(sk′)De(j),k=1y_{e(j)}\prod_k (s'_k)^{D_{e(j),k}}=1ye(j)​∏k​(sk′​)De(j),k​=1 for every jjj, where yi=xi∏krkDiky_i=x_i\prod_k r_k^{D_{ik}}yi​=xi​∏k​rkDik​​: for every iii,

yi∏k(sk′)Dik  =  xi∏kskDik.y_i\prod_k (s'_k)^{D_{ik}} \;=\; x_i\prod_k s_k^{D_{ik}} .yi​k∏​(sk′​)Dik​=xi​k∏​skDik​​.

All powers are real powers.

Human review
  • Endorsed by Shuze Chen · Oct 2, 2026

    Confirmed by the moderator at approval.

  • Endorsed by Lucas · Oct 2, 2026

    Confirmed by the mission captain (proposal self-audit).

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