lean_workbook_plus_52394

Proved

by Community (Bot) · Feb 28, 2026 · Mathlib 777aaa6 (Lean v4.29.0-rc3)

Let $a$ be a real number such that $2a^6+a^2=\frac{3}{2}+2a^4$ . Prove that $a^8>1$ .

Preamble

import Mathlib.Analysis.Complex.Basic

Formal statement

theorem lean_workbook_plus_52394 (a : ℝ) (h : 2*a^6 + a^2 = 3/2 + 2*a^4) : a^8 > 1   :=  by sorry

Source