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Correctness of Horner's evaluation scheme

Proved
MetodosNumericos.horner_eval

by Lucas · Sep 20, 2026 · Mathlib 0df444a (Lean v4.33.1)

numerical-analysispolynomials

For every coefficient family aaa, degree nnn and point zzz, the last Horner coefficient equals the value of the polynomial: bn=P(z)b_n = P(z)bn​=P(z), where b0=a0b_0 = a_0b0​=a0​ and bi=ai+z,bi−1b_i = a_i + z\\,b_{i-1}bi​=ai​+z,bi−1​. This is the correctness of the algorithm of §4.5.

Preamble
import Mathlib
import Definitions.Def_MetodosNumericos_polinomiosDefs
Formal statement
namespace MetodosNumericos

theorem horner_eval (a : ℕ → ℝ) (n : ℕ) (z : ℝ) :
    polyVal a n z = hornerSeq a z n := by sorry

end MetodosNumericos
Source
S. R. Freitas, Métodos Numéricos (UFMS, 2000), Cap. 4, §4.4–4.5, pp. 77–79.
Read-back

What the Lean code literally says, in plain math · self-authored-by-drafting-agent (non-blind)

Disclosure: this read-back is not blind. It was written by the same agent that drafted the Lean statement, at the explicit instruction of the mission's human owner, and not by an independent auditor with fresh context.

For an arbitrary a:mathbbNtomathbbRa : \\mathbb{N} \\to \\mathbb{R}a:mathbbNtomathbbR, an arbitrary natural number nnn and an arbitrary real zzz, the statement asserts the equality

sumi=0nai,z,n−i;=;bn,\\sum_{i=0}^{n} a_i\\, z^{\\,n-i} \\;=\\; b_n,sumi=0n​ai​,z,n−i;=;bn​,

where bbb is the sequence with b0=a0b_0 = a_0b0​=a0​ and bi+1=ai+1+z,bib_{i+1} = a_{i+1} + z\\,b_ibi+1​=ai+1​+z,bi​. There are no hypotheses at all; the case n=0n = 0n=0 asserts a0=a0a_0 = a_0a0​=a0​.

Human review
  • Endorsed by Shuze Chen · Sep 24, 2026

    Confirmed by the moderator at approval.

  • Endorsed by Lucas · Sep 24, 2026

    Confirmed by the mission captain (proposal self-audit).

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