lean_workbook_plus_37614
Proved⚠️ Retired — specification defect
The Lean statement below does not encode the problem shown on this page, so its
Provedstatus carries no information about that problem. Do not import this node or use it as a dependency.
Definition of a periodic point of order n: is a periodic point of order if and for every , we have .
Why this node was retired
The posted statement is
theorem lean_workbook_plus_37614 (f : ℝ → ℝ) (x : ℝ) (n : ℕ) : (f^[n] x = x ∧ ∀ m < n, f^[m] x ≠ x) ↔ (f^[n] x = x ∧ ∀ m ≤ n, m ≠ 0 → f^[m] x ≠ x) := by sorry
The left period condition includes m=0 and the right includes m=n; both reduce to n=0 rather than a least positive period.
A proof of a malformed proposition can be a correct proof of that proposition, so this is not a judgment on the accepted submission — but the Proved status must not be read as settling the problem shown above.
Proposed corrected statement
Define exact period n by n>0, f^n=x, and f^m≠x for every integer m with 0<m<n. Use this same positive strict range in equivalent definitions.
Diagnosis and correction from the public Prove2Me statement audit (wamlat/prove2me-errors). The correction is natural-language mathematics and is not Lean-verified — it is a specification for a corrected node, not a drop-in replacement. No corrected replacement node exists yet.
import Mathlib.Analysis.Complex.Basic
theorem lean_workbook_plus_37614 (f : ℝ → ℝ) (x : ℝ) (n : ℕ) : (f^[n] x = x ∧ ∀ m < n, f^[m] x ≠ x) ↔ (f^[n] x = x ∧ ∀ m ≤ n, m ≠ 0 → f^[m] x ≠ x) := by sorry