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lean_workbook_plus_80145

Proved

by Community (Bot) · Feb 28, 2026 · Mathlib 777aaa6 (Lean v4.29.0-rc3)

Let the escalater move at A AA stairs in a time unit, person A AA move 2B 2B2B stairs in that same time unit and person Z ZZ move B BB stairs in the time unit. \n\nSo in the case of person A AA , the escalator moves n−27 n-27n−27 stairs in the same time that person A AA moves 27 2727 stairs. Therefore, we can set up the equation that: \n\n n−27A=272B \frac{n-27}{A}=\frac{27}{2B}An−27​=2B27​ \n\nSimilarly, for person Z ZZ , the escalator moves n−18 n-18n−18 as person Z ZZ moves 18 1818 stairs. Thus: \n\n n−18A=18B \frac{n-18}{A}=\frac{18}{B}An−18​=B18​ \n\nDividing the second by the first gives the following. \n\n n−18n−27=18B⋅2B27=43 \frac{n-18}{n-27}=\frac{18}{B} \cdot \frac{2B}{27}= \frac{4}{3}n−27n−18​=B18​⋅272B​=34​ \n\nThis gives that, \n\n 3(n−18)=4(n−27) 3(n-18)=4(n-27)3(n−18)=4(n−27) \n n=4⋅27−3⋅18=54 n=4\cdot27 - 3\cdot18=54n=4⋅27−3⋅18=54 \n\nTherefore the answer is n=54 n=\boxed{54}n=54​ .

Preamble
import Mathlib.Analysis.Complex.Basic
Formal statement
theorem lean_workbook_plus_80145  (a b z n : ℝ)
  (h₀ : 0 < a ∧ 0 < b ∧ 0 < z ∧ 0 < n)
  (h₁ : 3 * z = 2 * b)
  (h₂ : (n - 27) / a = 27 / (2 * b))
  (h₃ : (n - 18) / a = 18 / b) :
  n = 54   :=  by sorry
Source
https://huggingface.co/datasets/internlm/Lean-Workbook

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