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Eq. (10): the singlet quartic coupling hhh is non-decreasing under one-loop running

Proved
NewMinimalStandardModel.singlet_quartic_nondecreasing

by Lucas · Oct 4, 2026 · Mathlib 0df444a (Lean v4.33.1)

mathematical-physicsoderenormalization-group

Let a,b∈Ra,b\in\mathbb Ra,b∈R and let h,k:R→Rh,k:\mathbb R\to\mathbb Rh,k:R→R. Suppose that at every t∈[a,b]t\in[a,b]t∈[a,b] the function hhh is differentiable with

(4π)2dhdt(t)=3h(t)2+12k(t)2,(4\pi)^2\frac{dh}{dt}(t) = 3h(t)^2 + 12k(t)^2,(4π)2dtdh​(t)=3h(t)2+12k(t)2,

the one-loop renormalization-group equation (10) for the singlet self-coupling hhh, with t=log⁡μt=\log\mut=logμ and kkk the Higgs–singlet coupling. Then hhh is non-decreasing on [a,b][a,b][a,b].

This is the elementary fact behind the triviality bound on hhh discussed with Fig. 1: the coupling can only grow with the renormalization scale.

Preamble
import Mathlib
import Definitions.Def_NewMinimalStandardModel_Defs
Formal statement
namespace NewMinimalStandardModel

theorem singlet_quartic_nondecreasing (h k : ℝ → ℝ) (a b : ℝ)
    (hODE : ∀ t ∈ Set.Icc a b,
      HasDerivAt h ((3 * h t ^ 2 + 12 * k t ^ 2) / (4 * Real.pi) ^ 2) t) :
    MonotoneOn h (Set.Icc a b) := by sorry

end NewMinimalStandardModel
Source
H. Davoudiasl, R. Kitano, T. Li, H. Murayama, The new Minimal Standard Model, Phys. Lett. B 609 (2005) 117-123, https://doi.org/10.1016/j.physletb.2005.01.026, Eq. (10), p. 121
Read-back

What the Lean code literally says, in plain math · Aristotle (Harmonic) - same agent that drafted the statements; NON-BLIND, not an independent auditor

NON-BLIND READ-BACK — NOT INDEPENDENT TESTIMONY. This read-back was written by the same agent that drafted the Lean statement, with full knowledge of the source paper and of the intended meaning. It was not produced by a blind, independent auditor and must not be treated as independent evidence of faithfulness. Reviewers should compare the Lean code against the source themselves.

For all functions h,k:R→Rh,k:\mathbb R\to\mathbb Rh,k:R→R and reals a,ba,ba,b: if for every ttt with a≤t≤ba\le t\le ba≤t≤b the function hhh has (two-sided) derivative at ttt equal to 3h(t)2+12k(t)2(4π)2\frac{3h(t)^2+12k(t)^2}{(4\pi)^2}(4π)23h(t)2+12k(t)2​, then for all s,t∈[a,b]s,t\in[a,b]s,t∈[a,b] with s≤ts\le ts≤t one has h(s)≤h(t)h(s)\le h(t)h(s)≤h(t). No assumption is made on kkk (not even continuity). If a>ba>ba>b the interval is empty and the conclusion is vacuous.

Human review
  • Endorsed by Shuze Chen · Oct 8, 2026

    Confirmed by the moderator at approval.

  • Endorsed by Lucas · Oct 8, 2026

    Confirmed by the mission captain (proposal self-audit).

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