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Conte–Fujikawa–Lakic (2007): K≤4d−1d+1K \le 4\frac{d-1}{d+1}K≤4d+1d−1​

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SmaleMeanValue.conte_fujikawa_lakic

by Lucas · Sep 30, 2026 · Mathlib 0df444a (Lean v4.33.1)

complex-analysispolynomialsunivalent-functions

Let PPP be a complex polynomial of degree d≥2d \ge 2d≥2 and let z∈Cz \in \mathbb Cz∈C with P′(z)≠0P'(z) \neq 0P′(z)=0. Then there is a critical point ccc of PPP with

∣P(z)−P(c)z−c∣≤4 d−1d+1 ∣P′(z)∣.\left| \frac{P(z) - P(c)}{z - c} \right| \le 4\,\frac{d-1}{d+1}\,|P'(z)|.​z−cP(z)−P(c)​​≤4d+1d−1​∣P′(z)∣.

This improves Smale's constant 444 for each fixed degree ddd.

Preamble
import Mathlib
open Polynomial
Formal statement
namespace SmaleMeanValue

theorem conte_fujikawa_lakic (P : ℂ[X]) (hP : 2 ≤ P.natDegree) (z : ℂ)
    (hz : P.derivative.eval z ≠ 0) :
    ∃ c : ℂ, P.derivative.eval c = 0 ∧
      ‖(P.eval z - P.eval c) / (z - c)‖ ≤
        (4 * ((P.natDegree : ℝ) - 1) / ((P.natDegree : ℝ) + 1)) *
          ‖P.derivative.eval z‖ := by sorry

end SmaleMeanValue
Source
Wikipedia, "Mean value problem", revision oldid=1374678764, https://en.wikipedia.org/w/index.php?title=Mean_value_problem&oldid=1374678764, section "Partial results"; Conte, Fujikawa, Lakic, Proc. AMS 135(10) (2007), 3295–3300, https://doi.org/10.1090/S0002-9939-07-08861-2
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What the Lean code literally says, in plain math · Aristotle (Harmonic) — same agent as the drafter; NON-BLIND

Disclosure — NOT an independent read-back. This read-back is non-blind: it was written by the same agent that drafted the Lean statement, with full knowledge of the source material and of the intended meaning. It must not be treated as independent testimony. Reviewers should compare the Lean code against the source themselves.

Let PPP be any polynomial with complex coefficients, and write ddd for its degree (the natural-number degree; for the zero polynomial this would be 000, but here it is excluded because d≥2d \ge 2d≥2 is assumed). Write P′P'P′ for the formal derivative of PPP and P(w)P(w)P(w) for evaluation at w∈Cw \in \mathbb Cw∈C. Let zzz be any complex number such that P′(z)≠0P'(z) \neq 0P′(z)=0. The statement asserts that there exists c∈Cc \in \mathbb Cc∈C with P′(c)=0P'(c) = 0P′(c)=0 and

∣P(z)−P(c)z−c∣≤4 (d−1)d+1 ∣P′(z)∣,\left| \frac{P(z) - P(c)}{z - c} \right| \le \frac{4\,(d-1)}{d+1}\,|P'(z)| ,​z−cP(z)−P(c)​​≤d+14(d−1)​∣P′(z)∣,

where 4(d−1)d+1\frac{4(d-1)}{d+1}d+14(d−1)​ is computed in the real numbers from ddd (the denominator d+1d+1d+1 is positive). Here ccc ranges over all complex numbers; the condition P′(c)=0P'(c) = 0P′(c)=0 says that ccc is a critical point of PPP. Because P′(z)≠0P'(z) \neq 0P′(z)=0 and P′(c)=0P'(c) = 0P′(c)=0, necessarily c≠zc \neq zc=z, so the denominator z−cz - cz−c is never zero and no division-by-zero convention is involved. The absolute values are the usual modulus on C\mathbb CC.

Human review
  • Endorsed by Shuze Chen · Sep 30, 2026

    Confirmed by the moderator at approval.

  • Endorsed by Lucas · Sep 30, 2026

    Confirmed by the mission captain (proposal self-audit).

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