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Coppersmith--Winograd coupled laser auxiliary inequality

Proved
mme_CW_auxiliary_inequality

by marwahaha · Aug 23, 2026 · Mathlib 0df444a (Lean v4.33.1)

algebraic-complexitycoppersmith-winogradlaser-methodmatrix-multiplicationsalem-spencer

Let q≥3q\ge3q≥3 and put τ=ωK/3\tau=\omega_K/3τ=ωK​/3, with ωK≥2\omega_K\ge2ωK​≥2. For positive real frequencies a,b,c,da,b,c,da,b,c,d satisfying

3a+6b+3c+3d=1,3a+6b+3c+3d=1,3a+6b+3c+3d=1,

the coupled tensor-square extraction gives

auxiliaryRHS⁡(q,τ,a,b,c,d)≤(q+2)2.\operatorname{auxiliaryRHS}(q,\tau,a,b,c,d)\le(q+2)^2.auxiliaryRHS(q,τ,a,b,c,d)≤(q+2)2.

The right-hand side is the square of the border-rank base of TqT_qTq​. The left-hand side is exactly the normalized expression on journal p. 269 after substituting the five marginals from equation (13). This theorem is the hard Section 8 laser step: its proof must exhibit the Salem--Spencer-pruned direct sums and use the coupled constituent value, rather than count incompatible blocks.

Preamble
import Definitions.Def_mme_CW_auxiliary_RHS
import Definitions.Def_mme_omega_strassen
open MME
universe u
Formal statement
theorem mme_CW_auxiliary_inequality
    {K : Type u} [Field K]
    (q : ℕ) (hq : 3 ≤ q)
    (homega : 2 ≤ matMulExp_strassen K)
    (a b c d : ℝ)
    (ha : 0 < a) (hb : 0 < b) (hc : 0 < c) (hd : 0 < d)
    (hnorm : 3 * a + 6 * b + 3 * c + 3 * d = 1) :
    auxiliaryRHS q (matMulExp_strassen K / 3) a b c d ≤
      ((q : ℝ) + 2) ^ (2 : ℕ) := by sorry
Source
D. Coppersmith and S. Winograd, Matrix Multiplication via Arithmetic Progressions, Journal of Symbolic Computation 9 (1990), equations (11)--(13), coupled extraction on journal pp. 265--269 (PDF pp. 15--19), and the coupled-piece lemma on journal pp. 270--272; https://www.sciencedirect.com/science/article/pii/S0747717108800132

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