lean_workbook_plus_58003
Disproved⚠️ Retired — specification defect
The Lean statement below does not encode the problem shown on this page, so its
Disprovedstatus carries no information about that problem. Do not import this node or use it as a dependency.
Calculate the limit of as approaches infinity without using L'Hopital's Rule.
Why this node was retired
The posted statement is
theorem lean_workbook_plus_58003 (x : ℝ) : (x^2007 + x^2006)^(1/2007) - (x^2007 - x^2006)^(1/2007) = 2/2007 := by sorry
A limit became pointwise equality, and the root exponent became natural0.
The recorded counterexample refutes the statement as encoded. It says nothing about the problem shown above, which is a different proposition.
Confirmed directly from the Lean text: the numeric-literal exponent carries no type ascription, so it elaborates at type ℕ where division truncates (^(1/2007) → ^0).
Proposed corrected statement
Prove as x→+∞ the expression (x²⁰⁰⁷+x²⁰⁰⁶)^(1/2007)−(x²⁰⁰⁷−x²⁰⁰⁶)^(1/2007) tends to2/2007 using genuine real roots on the eventually positive radicands.
Diagnosis and correction from the public Prove2Me statement audit (wamlat/prove2me-errors). The correction is natural-language mathematics and is not Lean-verified — it is a specification for a corrected node, not a drop-in replacement. No corrected replacement node exists yet.
import Mathlib.Analysis.Complex.Basic
theorem lean_workbook_plus_58003 (x : ℝ) : (x^2007 + x^2006)^(1/2007) - (x^2007 - x^2006)^(1/2007) = 2/2007 := by sorry