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First Friedmann equation in density parameters: H2/H02=Ω0,Ra−4+Ω0,Ma−3+Ω0,ka−2+Ω0,ΛH^2/H_0^2 = \Omega_{0,R}a^{-4} + \Omega_{0,M}a^{-3} + \Omega_{0,k}a^{-2} + \Omega_{0,\Lambda}H2/H02​=Ω0,R​a−4+Ω0,M​a−3+Ω0,k​a−2+Ω0,Λ​

Proved
FriedmannEquations.first_friedmann_density_parameters

by Lucas · Sep 27, 2026 · Mathlib 0df444a (Lean v4.33.1)

cosmologyfriedmann-equationsgeneral-relativity

Let G>0G>0G>0 and Λ,k∈R\Lambda,k\in\mathbb RΛ,k∈R; let t0t_0t0​ ("today") and ttt be times with R(t0)≠0R(t_0)\ne 0R(t0​)=0, R(t)≠0R(t)\ne0R(t)=0 and H0:=H(t0)≠0H_0 := H(t_0)\neq 0H0​:=H(t0​)=0, and let a=R(t)/R(t0)a = R(t)/R(t_0)a=R(t)/R(t0​). Suppose the density consists of radiation and matter, ρ(s)=ρR a(s)−4+ρM a(s)−3\rho(s) = \rho_R\,a(s)^{-4} + \rho_M\,a(s)^{-3}ρ(s)=ρR​a(s)−4+ρM​a(s)−3 for all sss (with a(s)=R(s)/R(t0)a(s)=R(s)/R(t_0)a(s)=R(s)/R(t0​)), and that the first Friedmann equation H2=8πGρ3−kR2+Λ3H^2 = \frac{8\pi G\rho}{3} - \frac{k}{R^2} + \frac{\Lambda}{3}H2=38πGρ​−R2k​+3Λ​ holds at ttt and at t0t_0t0​. With the present-day density parameters

Ω0,R=ρRρc,Ω0,M=ρMρc,Ω0,Λ=Λ/(8πG)ρc=Λ3H02,Ω0,k=1−Ω0,  Ω0=Ω0,R+Ω0,M+Ω0,Λ,\Omega_{0,R} = \frac{\rho_R}{\rho_c},\quad \Omega_{0,M} = \frac{\rho_M}{\rho_c},\quad \Omega_{0,\Lambda} = \frac{\Lambda/(8\pi G)}{\rho_c} = \frac{\Lambda}{3H_0^2},\quad \Omega_{0,k} = 1 - \Omega_0,\ \ \Omega_0 = \Omega_{0,R}+\Omega_{0,M}+\Omega_{0,\Lambda},Ω0,R​=ρc​ρR​​,Ω0,M​=ρc​ρM​​,Ω0,Λ​=ρc​Λ/(8πG)​=3H02​Λ​,Ω0,k​=1−Ω0​,  Ω0​=Ω0,R​+Ω0,M​+Ω0,Λ​,

where ρc=3H02/(8πG)\rho_c = 3H_0^2/(8\pi G)ρc​=3H02​/(8πG), one has

H(t)2H02=Ω0,Ra−4+Ω0,Ma−3+Ω0,ka−2+Ω0,Λ.\frac{H(t)^2}{H_0^2} = \Omega_{0,R}a^{-4} + \Omega_{0,M}a^{-3} + \Omega_{0,k}a^{-2} + \Omega_{0,\Lambda}.H02​H(t)2​=Ω0,R​a−4+Ω0,M​a−3+Ω0,k​a−2+Ω0,Λ​.

Here the vacuum energy is counted in the total Ω0\Omega_0Ω0​ (vacuum density Λ/8πG\Lambda/8\pi GΛ/8πG, cf. section Cosmological constant).

Preamble
import Definitions.Def_FriedmannEquations_Defs
import Mathlib

open FriedmannEquations
Formal statement
theorem FriedmannEquations.first_friedmann_density_parameters
    (G Λ k ρR ρM : ℝ) (hG : 0 < G) (R ρ : ℝ → ℝ) (t t₀ : ℝ)
    (hR : R t ≠ 0) (hR₀ : R t₀ ≠ 0) (hH₀ : hubble R t₀ ≠ 0)
    (hρ : ∀ s, ρ s = ρR / (R s / R t₀) ^ 4 + ρM / (R s / R t₀) ^ 3)
    (h₁ : FirstFriedmannEq G Λ k R ρ t) (h₁₀ : FirstFriedmannEq G Λ k R ρ t₀) :
    let a := R t / R t₀
    let H₀ := hubble R t₀
    let ΩR := densityParameter G H₀ ρR
    let ΩM := densityParameter G H₀ ρM
    let ΩΛ := densityParameter G H₀ (Λ / (8 * Real.pi * G))
    let Ωk := 1 - (ΩR + ΩM + ΩΛ)
    hubble R t ^ 2 / H₀ ^ 2 =
      ΩR * a ^ (-4 : ℤ) + ΩM * a ^ (-3 : ℤ) + Ωk * a ^ (-2 : ℤ) + ΩΛ := by sorry
Source
Wikipedia, "Friedmann equations", revision oldid=1374073387, https://en.wikipedia.org/w/index.php?title=Friedmann_equations&oldid=1374073387 (the PDF supplied with this proposal), section "Density parameter", p. 5 (display after "in terms of the present values of the density parameters").
Read-back

What the Lean code literally says, in plain math · Aristotle (Harmonic)

NOTE — NON-BLIND READ-BACK. This read-back is not independent testimony. It was written by the same agent (Aristotle, by Harmonic) that drafted the Lean statements, with full knowledge of the source article and of the intended meaning. It was produced at the explicit request of the proposal owner. Reviewers must not treat it as a blind audit; an independent read-back is still recommended.

Fix reals G,Λ,k,ρR,ρMG,\Lambda,k,\rho_R,\rho_MG,Λ,k,ρR​,ρM​ with G>0G>0G>0, functions R,ρ:R→RR,\rho:\mathbb R\to\mathbb RR,ρ:R→R and times t,t0t,t_0t,t0​. Assume R(t)≠0R(t)\neq0R(t)=0, R(t0)≠0R(t_0)\ne0R(t0​)=0, and H0:=R˙(t0)/R(t0)≠0H_0 := \dot R(t_0)/R(t_0)\neq 0H0​:=R˙(t0​)/R(t0​)=0; assume for every real sss,

ρ(s)=ρR(R(s)/R(t0))4+ρM(R(s)/R(t0))3\rho(s) = \frac{\rho_R}{(R(s)/R(t_0))^4} + \frac{\rho_M}{(R(s)/R(t_0))^3}ρ(s)=(R(s)/R(t0​))4ρR​​+(R(s)/R(t0​))3ρM​​

(junk: division by 000 gives 000 where R(s)=0R(s)=0R(s)=0); and assume at ttt and at t0t_0t0​ (same kkk, Λ\LambdaΛ)

(R˙(s)R(s))2=8πGρ(s)3−kR(s)2+Λ3.\Big(\frac{\dot R(s)}{R(s)}\Big)^2 = \frac{8\pi G\rho(s)}{3} - \frac{k}{R(s)^2} + \frac{\Lambda}{3}.(R(s)R˙(s)​)2=38πGρ(s)​−R(s)2k​+3Λ​.

Define a=R(t)/R(t0)a = R(t)/R(t_0)a=R(t)/R(t0​), ρc=3H02/(8πG)\rho_c = 3H_0^2/(8\pi G)ρc​=3H02​/(8πG), ΩR=ρR/ρc\Omega_R = \rho_R/\rho_cΩR​=ρR​/ρc​, ΩM=ρM/ρc\Omega_M = \rho_M/\rho_cΩM​=ρM​/ρc​, ΩΛ=(Λ/(8πG))/ρc\Omega_\Lambda = \big(\Lambda/(8\pi G)\big)/\rho_cΩΛ​=(Λ/(8πG))/ρc​, Ωk=1−(ΩR+ΩM+ΩΛ)\Omega_k = 1-(\Omega_R+\Omega_M+\Omega_\Lambda)Ωk​=1−(ΩR​+ΩM​+ΩΛ​). Conclusion:

(R˙(t)/R(t))2H02=ΩR a−4+ΩM a−3+Ωk a−2+ΩΛ,\frac{(\dot R(t)/R(t))^2}{H_0^2} = \Omega_R\,a^{-4} + \Omega_M\,a^{-3} + \Omega_k\,a^{-2} + \Omega_\Lambda,H02​(R˙(t)/R(t))2​=ΩR​a−4+ΩM​a−3+Ωk​a−2+ΩΛ​,

with integer powers a−na^{-n}a−n.

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