Theorem 5:1, eq. (5:3d) — $(r_i,Ap_i)=(p_i,Ap_i)$ and $(r_i,Ap_j)=0$ for $i\ne j, j+1$

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Theorem 5:1, eq. (5:3d) — $(r_i,Ap_i)=(p_i,Ap_i)$ and $(r_i,Ap_j)=0$ for $i\ne j, j+1$ · Prove2Me