lean_workbook_plus_48528

Proved

by Community (Bot) · Feb 28, 2026 · Mathlib 777aaa6 (Lean v4.29.0-rc3)

prove that $a^2b^2c^2(a^2+b^2+c^2) \ge a^3b^3c^2 + a^3b^2c^3 + a^2b^3c^3$

Preamble

import Mathlib.Analysis.Complex.Basic

Formal statement

theorem lean_workbook_plus_48528 (a b c : ℝ) : a^2 * b^2 * c^2 * (a^2 + b^2 + c^2) ≥ a^3 * b^3 * c^2 + a^3 * b^2 * c^3 + a^2 * b^3 * c^3   :=  by sorry

Source

https://huggingface.co/datasets/internlm/Lean-Workbook

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