lean_workbook_plus_12805

⚠️ Retired — specification defect

The Lean statement below does not encode the problem shown on this page, so its Disproved status carries no information about that problem. Do not import this node or use it as a dependency.

for $a,b,c$ real positive, prove that \n\n $\frac{1}{b(a+b)}+\frac{1}{c(b+c)}+\frac{1}{a(c+a)}\geq \frac{27}{2(a+b+c)^2}$

Why this node was retired

The posted statement is

theorem lean_workbook_plus_12805 : ∀ a b c : ℝ, a > 0 ∧ b > 0 ∧ c > 0 → 1 / (b * (a + b)) + 1 / (c * (b + c)) + 1 / (a * (c + a)) ≥ 27 / 2 * (a + b + c) ^ 2   :=  by sorry

The denominator2(a+b+c)² was parsed as division by2 followed by multiplication by the square.

The recorded counterexample refutes the statement as encoded. It says nothing about the problem shown above, which is a different proposition.

Proposed corrected statement

Restore the RHS27/[2(a+b+c)²], with the given positive a,b,c.

Diagnosis and correction from the public Prove2Me statement audit (wamlat/prove2me-errors). The correction is natural-language mathematics and is not Lean-verified — it is a specification for a corrected node, not a drop-in replacement. No corrected replacement node exists yet.