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Exact count of maps with a prescribed zero subset sum

Proved
Erdos624.zero_sum_count

by Ethan Cheung Wang · Oct 23, 2026 · Mathlib 0df444a (Lean v4.33.1)

combinatoricserdos-problems

Theorem. Let UUU be a finite set, m≥0m\ge0m≥0, and A⊆UA\subseteq UA⊆U nonempty. Then

2m⋅∣{h:U→F2m: ∑a∈Ah(a)=0}∣=∣(F2m)U∣.2^m\cdot\bigl|\{h:U\to\mathbb F_2^m:\ \textstyle\sum_{a\in A}h(a)=0\}\bigr|=\bigl|(\mathbb F_2^m)^U\bigr|.2m⋅​{h:U→F2m​: ∑a∈A​h(a)=0}​=​(F2m​)U​.

With m=k−1m=k-1m=k−1 and ∣U∣=2k|U|=2^k∣U∣=2k this says each nonempty AAA lies in exactly a 2/n2/n2/n fraction of the zero-sum families Fh\mathcal F_hFh​, the averaged capacity identity of the fractional obstruction for Erdős Problem 624.

Preamble
import Mathlib
import Definitions.Def_Erdos624_defs
open Finset
Formal statement
namespace Erdos624

theorem zero_sum_count {U : Type*} [Fintype U] [DecidableEq U] (m : ℕ) (A : Finset U)
    (hA : A.Nonempty) :
    2 ^ m * #((univ : Finset (U → (Fin m → ZMod 2))).filter (fun h => ∑ a ∈ A, h a = 0)) =
      Fintype.card (U → (Fin m → ZMod 2)) := by sorry

end Erdos624
Source
Erdős Problem 624 (https://www.erdosproblems.com/624); definitions from Formal Conjectures 624.lean; (19)–(20) of claim from GPT 6.1 Sol (fifth answer, Oct 23 2026), Lean-verified by Grok Bot for Ethan Cheung (Oct 23 2026)

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