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Special exponent k=1k=1k=1: the Dris index has Ω(s)≥3\Omega(s) \ge 3Ω(s)≥3

Proved
OddPerfectNumber.dris_index_bigOmega_ge_three_at_k_one

by Gabewhigham · Sep 11, 2026 · Mathlib 0df444a (Lean v4.33.1)

number-theory

Consider an odd perfect number written in Euler form with special exponent k=1k = 1k=1, that is, N=p m2N = p\,m^{2}N=pm2 with ppp prime, mmm odd and p∤mp \nmid mp∤m — the configuration predicted by the Descartes–Frenicle–Sorli conjecture. The Dris relations then read

2m2=σ(p) s,σ(m2)=p s,2m^{2} = \sigma(p)\,s, \qquad \sigma(m^{2}) = p\,s,2m2=σ(p)s,σ(m2)=ps,

with Dris index s=σ(m2)/ps = \sigma(m^{2})/ps=σ(m2)/p. The assertion is that such an index cannot be too simple:

Ω(s) ≥ 3,\Omega(s) \ \ge\ 3,Ω(s) ≥ 3,

where Ω\OmegaΩ counts prime factors with multiplicity (in Lean, the length of s.primeFactorsList). In particular sss is neither 111, nor a prime, nor a product of two primes, so s≥27s \ge 27s≥27.

The reason is a counting one. Since σ(m2)=p s\sigma(m^{2}) = p\,sσ(m2)=ps has ppp-adic valuation 111, at most one of the local divisor sums σ(q2vq(m))\sigma(q^{2v_q(m)})σ(q2vq​(m)), q∣mq \mid mq∣m, can be divisible by ppp; every other local divisor sum is a factor >1> 1>1 of sss, and these factors are pairwise coprime. Hence ω(m)≤1+Ω(s)\omega(m) \le 1 + \Omega(s)ω(m)≤1+Ω(s). Sylvester's bound ω(N)≥5\omega(N) \ge 5ω(N)≥5 gives ω(m)≥4\omega(m) \ge 4ω(m)≥4, and the claim follows.

No congruence conditions on ppp or on mmm beyond oddness are needed.

Preamble
import Mathlib
Formal statement
namespace OddPerfectNumber

theorem dris_index_bigOmega_ge_three_at_k_one (p m s : Nat)
    (hp : p.Prime) (hm : Odd m) (hpm : ¬ p ∣ m)
    (h1 : 2 * m ^ 2 = (∑ d ∈ p.divisors, d) * s)
    (h2 : (∑ x ∈ (m ^ 2).divisors, x) = p * s) :
    3 ≤ s.primeFactorsList.length := by
  sorry

end OddPerfectNumber
Source
J. A. B. Dris, The abundancy index of divisors of odd perfect numbers, Journal of Integer Seq. 15 (2012), Article 12.4.4, Section 2 (Dris parametrisation, index s = sigma(m^2)/p^k); J. J. Sylvester (1888) for omega(N) >= 5.

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