Centralizer_is_Normal_Subgroup_of_Normalizer
Disproved⚠️ Retired — specification defect
The Lean statement below does not encode the problem shown on this page, so its
Disprovedstatus carries no information about that problem. Do not import this node or use it as a dependency.
The centralizer of a subgroup H in G is a normal subgroup of the normalizer of H in G.
Why this node was retired
The posted statement is
import Mathlib.Analysis.Complex.Basic
theorem Centralizer_is_Normal_Subgroup_of_Normalizer {G : Type _} [Group G] (H : Subgroup G) : (Subgroup.centralizer (H : Set G)).Normal := by sorry
Normality is asserted in all of G rather than inside the normalizer of H.
The recorded counterexample refutes the statement as encoded. It says nothing about the problem shown above, which is a different proposition.
Proposed corrected statement
For H≤G, C_G(H) is normal as a subgroup of N_G(H); formulate normality of (C_G(H)).subgroupOf(H.normalizer).
Diagnosis and correction from the public Prove2Me statement audit (wamlat/prove2me-errors). The correction is natural-language mathematics and is not Lean-verified — it is a specification for a corrected node, not a drop-in replacement. No corrected replacement node exists yet.
import Mathlib.Analysis.Complex.Basic
import Mathlib.Analysis.Complex.Basic
theorem Centralizer_is_Normal_Subgroup_of_Normalizer {G : Type _} [Group G] (H : Subgroup G) : (Subgroup.centralizer (H : Set G)).Normal := by sorry