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Section 5.1 — Sixfold cubic normalization

Proved
FourColor.cubic_normalization

by Minghui · Sep 26, 2026 · Mathlib c5ea003 (Lean v4.30.0)

four-color-theoremgraph-theory

For every finite hypermap HHH on nnn darts, there is a hypermap QQQ on exactly 6n6n6n darts that is plain and cubic, such that

Planar⁡(Q)  ⟺  Planar⁡(H),Bridgeless⁡(Q)  ⟺  Bridgeless⁡(H),\operatorname{Planar}(Q)\iff\operatorname{Planar}(H),\qquad \operatorname{Bridgeless}(Q)\iff\operatorname{Bridgeless}(H),Planar(Q)⟺Planar(H),Bridgeless(Q)⟺Bridgeless(H),

and every existence proof of a four-coloring of QQQ gives a four-coloring of HHH. No planarity or bridgelessness assumption is needed to construct QQQ; these properties are preserved in both directions. The case n=0n=0n=0 is included.

Formalization note: source-derived existential interface to the actual six-tag cubification construction, corresponding to plain_cube, cubic_cube, planar_cube, bridgeless_cube and cube_colorable. The internal data structure may be Lean-native, but the count and preservation conclusions are fixed.

Notation: D={0,…,n−1}D=\{0,\ldots,n-1\}D={0,…,n−1} is the dart set, n=∣D∣n = |D|n=∣D∣ its size, and p=νHp = \nu_Hp=νH​ is the node permutation. Write e,fe,fe,f for the edge and face permutations, with p(f(e(d)))=dp(f(e(d)))=dp(f(e(d)))=d. Edge, node and face counts E,N,FE,N,FE,N,F are numbers of permutation orbits, including singleton orbits. The component count CCC uses the equivalence generated by all three permutations. Planarity means the exact Euler equality E+N+F=n+2CE+N+F=n+2CE+N+F=n+2C, and connectedness means C=1C=1C=1.

A plain hypermap has a fixed-point-free involution eee. Cubic means every node orbit has size three; precubic means every node orbit has size at most three. Bridgeless means ddd and e(d)e(d)e(d) never lie in the same face orbit. A kkk-coloring is a map D→{0,…,k−1}D\to\{0,\ldots,k-1\}D→{0,…,k−1} constant on face orbits and different across each edge step. No requirement uses all available colors. The empty dart set has zero components, is planar, and is colorable, but is not connected.

An admissible hypermap is planar, bridgeless, plain and precubic. A minimal counterexample is a non-four-colorable admissible hypermap such that every admissible hypermap with fewer darts is four-colorable. Minimality includes all finite carriers through their enumeration by Fin⁡(m)\operatorname{Fin}(m)Fin(m); cubicity, connectedness and lower face-degree bounds are not assumed.

Source: Georges Gonthier, A Computer-Checked Proof of the Four Colour Theorem (2005), https://www.microsoft.com/en-us/research/wp-content/uploads/2012/10/4colproof.pdf; Section 5.1, PDF p. 26, paragraph on PDF p. 26 describing cubification; Section 3, PDF p. 6, cubic-map reduction. Relevant displays are unnumbered. Pinned executable reference: https://github.com/rocq-community/fourcolor/blob/c1d6b1cd5288bea4b067aac13cdde3c18dffe018/theories/proof/cube.v#L44; https://github.com/rocq-community/fourcolor/blob/c1d6b1cd5288bea4b067aac13cdde3c18dffe018/theories/proof/cube.v#L89.

Preamble
import Definitions.Def_FourColor_Hypermap
Formal statement
namespace FourColor
universe u
theorem cubic_normalization :
  ∀ (n : ℕ) (H : Hypermap n), ∃ K : Hypermap (6 * n),
    K.Plain ∧ K.Cubic ∧ (K.Planar ↔ H.Planar) ∧
      (K.Bridgeless ↔ H.Bridgeless) ∧ (K.FourColorable → H.FourColorable) := by sorry
end FourColor
Source
Georges Gonthier, A Computer-Checked Proof of the Four Colour Theorem (2005), https://www.microsoft.com/en-us/research/wp-content/uploads/2012/10/4colproof.pdf; Section 5.1, PDF p. 26, paragraph on PDF p. 26 describing cubification; Section 3, PDF p. 6, cubic-map reduction. Relevant displays are unnumbered. Pinned executable reference: https://github.com/rocq-community/fourcolor/blob/c1d6b1cd5288bea4b067aac13cdde3c18dffe018/theories/proof/cube.v#L44; https://github.com/rocq-community/fourcolor/blob/c1d6b1cd5288bea4b067aac13cdde3c18dffe018/theories/proof/cube.v#L89.
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What the Lean code literally says, in plain math · gpt-6

CubicNormalization. Let n∈Nn\in\mathbb Nn∈N, Dn={0,…,n−1}D_n=\{0,\ldots,n-1\}Dn​={0,…,n−1} (empty if n=0n=0n=0), and let H=(e,ν,ϕ)H=(e,\nu,\phi)H=(e,ν,ϕ) be three permutations of DnD_nDn​ with ν(ϕ(e(x)))=x\nu(\phi(e(x)))=xν(ϕ(e(x)))=x for every x∈Dnx\in D_nx∈Dn​. The proposition asserts the existence of permutations eK,νK,ϕKe_K,\nu_K,\phi_KeK​,νK​,ϕK​ of D6n={0,…,6n−1}D_{6n}=\{0,\ldots,6n-1\}D6n​={0,…,6n−1} with νK(ϕK(eK(x)))=x\nu_K(\phi_K(e_K(x)))=xνK​(ϕK​(eK​(x)))=x for all xxx, such that all of the following hold. Every x∈D6nx\in D_{6n}x∈D6n​ satisfies eK(eK(x))=xe_K(e_K(x))=xeK​(eK​(x))=x and eK(x)≠xe_K(x)\ne xeK​(x)=x, and every νK\nu_KνK​-cycle has exactly three elements. For each triple J=H,KJ=H,KJ=H,K, set dH=nd_H=ndH​=n, dK=6nd_K=6ndK​=6n; let EJ,NJ,FJE_J,N_J,F_JEJ​,NJ​,FJ​ count its edge, node, and face cycles, where a σ\sigmaσ-cycle uses ∃j∈Z, σj(x)=y\exists j\in\mathbb Z,\ \sigma^j(x)=y∃j∈Z, σj(x)=y; and let CJC_JCJ​ count the classes of the equivalence relation generated by its edge, node, and face permutation steps. Then EK+NK+FK=6n+2CKE_K+N_K+F_K=6n+2C_KEK​+NK​+FK​=6n+2CK​ if and only if EH+NH+FH=n+2CHE_H+N_H+F_H=n+2C_HEH​+NH​+FH​=n+2CH​. Also (∀x∈D6n, ¬∃j∈Z, ϕKj(x)=eK(x))(\forall x\in D_{6n},\ \neg\exists j\in\mathbb Z,\ \phi_K^j(x)=e_K(x))(∀x∈D6n​, ¬∃j∈Z, ϕKj​(x)=eK​(x)) if and only if (∀x∈Dn, ¬∃j∈Z, ϕj(x)=e(x))(\forall x\in D_n,\ \neg\exists j\in\mathbb Z,\ \phi^j(x)=e(x))(∀x∈Dn​, ¬∃j∈Z, ϕj(x)=e(x)). Finally, if there exists cK:D6n→{0,1,2,3}c_K:D_{6n}\to\{0,1,2,3\}cK​:D6n​→{0,1,2,3} constant on each ϕK\phi_KϕK​-cycle with cK(eK(x))≠cK(x)c_K(e_K(x))\ne c_K(x)cK​(eK​(x))=cK​(x) for every xxx, then there exists cH:Dn→{0,1,2,3}c_H:D_n\to\{0,1,2,3\}cH​:Dn​→{0,1,2,3} constant on each ϕ\phiϕ-cycle with cH(e(x))≠cH(x)c_H(e(x))\ne c_H(x)cH​(e(x))=cH​(x) for every xxx. There is no converse coloring implication, no requirement to use all four colors, and no map between the two dart sets is specified. There is no additional hypothesis on the input triple. Negative powers use inverses, and generated equivalence allows reflexivity, symmetry, and transitivity. If n=0n=0n=0, both dart sets are empty, all counts are zero, the universal dart conditions are vacuous, and empty colorings exist.

Human review
  • Endorsed by Shuze Chen · Sep 27, 2026

    Confirmed by the moderator at approval.

  • Endorsed by Minghui · Sep 27, 2026

    Confirmed by the mission captain (proposal self-audit).

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