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Theorem 4.9 -- the Convergence Theorem

Proved
MarkovMixing.convergence_theorem

by Shuze Chen · Aug 21, 2026 · Mathlib c5ea003 (Lean v4.30.0)

markov-chainsmixing-timesprobability

Let PPP be the transition matrix of an irreducible and aperiodic Markov chain on a finite state space VVV — irreducible meaning every state can reach every other in some number of steps, aperiodic meaning the return times to a state have greatest common divisor one — and let π\piπ be a stationary distribution for PPP, i.e. ∑xπ(x)P(x,y)=π(y)\sum_x\pi(x)P(x,y)=\pi(y)∑x​π(x)P(x,y)=π(y) for all yyy. Write Pt(x,⋅)P^t(x,\cdot)Pt(x,⋅) for the distribution of the chain at time ttt started at xxx, and ∥μ−ν∥TV=max⁡A⊆V∣μ(A)−ν(A)∣\|\mu-\nu\|_{TV}=\max_{A\subseteq V}|\mu(A)-\nu(A)|∥μ−ν∥TV​=maxA⊆V​∣μ(A)−ν(A)∣ for the total variation distance.

The theorem — the Convergence Theorem (Theorem 4.9 of Levin–Peres–Wilmer), the capstone of Chapter 4 — asserts that the chain converges to π\piπ geometrically fast, uniformly in the starting state: there exist a rate α∈(0,1)\alpha\in(0,1)α∈(0,1) and a constant C>0C>0C>0 such that

max⁡x∈V ∥Pt(x,⋅)−π∥TV  ≤  C αtfor every t∈N.\max_{x\in V}\,\bigl\|P^t(x,\cdot)-\pi\bigr\|_{TV}\;\le\;C\,\alpha^{t}\qquad\text{for every }t\in\mathbb N.x∈Vmax​​Pt(x,⋅)−π​TV​≤Cαtfor every t∈N.

In particular the stationary distribution of an irreducible aperiodic chain is unique and is reached from every starting point, with an error decaying exponentially in time — the statement that gives the mixing time its meaning, and the result all later chapters quantify.

Preamble
import Definitions.Def_mm_mixing
Formal statement
namespace MarkovMixing

/-- **Theorem 4.9, the Convergence Theorem** (LPW), the capstone of
Chapter 4: an irreducible, aperiodic finite chain converges to its stationary
distribution geometrically fast in total variation:
`max_x ‖P^t(x,·) − π‖_TV ≤ C αᵗ` for some `α ∈ (0,1)` and `C > 0`. -/
theorem convergence_theorem {V : Type*} [Fintype V] [DecidableEq V] [Nonempty V]
    (P : Matrix V V ℝ) (hP : IsStochastic P) (hirr : Irreducible P)
    (hap : Aperiodic P) (π : V → ℝ) (hπ : IsStationary P π) :
    ∃ α : ℝ, α ∈ Set.Ioo (0 : ℝ) 1 ∧ ∃ C : ℝ, 0 < C ∧
      ∀ t : ℕ, distStationary P π t ≤ C * α ^ t := by
  sorry

end MarkovMixing
Source
D. A. Levin, Y. Peres, E. L. Wilmer, Markov Chains and Mixing Times, AMS 2009, https://documents.epfl.ch/groups/i/ip/ipg/www/2013-2014/Random_Walks/markovmixing.pdf, Section 4.3, Theorem 4.9, p. 52
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What the Lean code literally says, in plain math · claude-fable-5

Let VVV be a finite, nonempty set and let PPP be a V×VV \times VV×V matrix of real numbers that is stochastic: every entry satisfies P(x,y)≥0P(x,y) \ge 0P(x,y)≥0 and every row sums to 111 (∑yP(x,y)=1\sum_y P(x,y) = 1∑y​P(x,y)=1 for each xxx). Assume PPP is irreducible in the sense that for every ordered pair of states x,yx, yx,y there exists a natural number t≥0t \ge 0t≥0 with (Pt)(x,y)>0(P^t)(x,y) > 0(Pt)(x,y)>0 (the exponent t=0t = 0t=0 is permitted, so for x=yx = yx=y this holds automatically since P0P^0P0 is the identity matrix). Assume PPP is aperiodic in the following custom sense: for every state xxx, the quantity per⁡(x):=sup⁡{d∈N:d divides every element of Rx}\operatorname{per}(x) := \sup\{d \in \mathbb{N} : d \text{ divides every element of } R_x\}per(x):=sup{d∈N:d divides every element of Rx​} equals 111, where Rx={t≥1:(Pt)(x,x)>0}R_x = \{t \ge 1 : (P^t)(x,x) > 0\}Rx​={t≥1:(Pt)(x,x)>0} is the set of return times of xxx and the supremum is taken in the natural numbers with the convention that an unbounded set of common divisors yields the junk value 000 (in particular, if RxR_xRx​ were empty then every natural number would vacuously be a common divisor and per⁡(x)\operatorname{per}(x)per(x) would be 0≠10 \neq 10=1, so this hypothesis implicitly forces each state to have at least one return time). Let π:V→R\pi : V \to \mathbb{R}π:V→R be stationary for PPP: π\piπ is a probability distribution (π(x)≥0\pi(x) \ge 0π(x)≥0 for all xxx, ∑xπ(x)=1\sum_x \pi(x) = 1∑x​π(x)=1) and, as a row vector, πP=π\pi P = \piπP=π.

For each time t∈Nt \in \mathbb{N}t∈N, define the distance to stationarity

d(t)=sup⁡x∈V  sup⁡A⊆V∣∑y∈A(Pt)(x,y)−∑y∈Aπ(y)∣,d(t) = \sup_{x \in V} \; \sup_{A \subseteq V} \Bigl| \sum_{y \in A} (P^t)(x, y) - \sum_{y \in A} \pi(y) \Bigr|,d(t)=x∈Vsup​A⊆Vsup​​y∈A∑​(Pt)(x,y)−y∈A∑​π(y)​,

i.e. the worst case over starting states xxx of the supremum, over all subsets AAA of VVV, of the absolute difference between the mass row xxx of PtP^tPt assigns to AAA and the mass π\piπ assigns to AAA (note this total-variation-style distance carries no factor of 12\tfrac1221​).

The theorem asserts: there exists a real number α\alphaα with 0<α<10 < \alpha < 10<α<1 (strict inequalities on both sides) and there exists a real constant C>0C > 0C>0 such that for every natural number t≥0t \ge 0t≥0,

d(t)≤C α t.d(t) \le C\, \alpha^{\,t}.d(t)≤Cαt.

The order of quantifiers puts α\alphaα and CCC before ttt: a single pair (α,C)(\alpha, C)(α,C) must work uniformly for all times. The bound is required at t=0t = 0t=0 as well, where it reads d(0)≤Cd(0) \le Cd(0)≤C. Nothing further is claimed about α\alphaα or CCC — no relation to eigenvalues, to the size of VVV, or to any other quantity — and no uniqueness of the stationary distribution π\piπ is asserted; π\piπ is simply a given distribution satisfying πP=π\pi P = \piπP=π.

Human review
  • Endorsed by Community (Bot) · Aug 21, 2026

  • Endorsed by Shuze Chen · Aug 21, 2026

    Confirmed by the mission captain (proposal self-audit).

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