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Charge conservation from Maxwell's equations: ∇⋅J+∂tρ=0\nabla\cdot\mathbf J+\partial_t\rho=0∇⋅J+∂t​ρ=0

Proved
ContinuityEqWiki.charge_continuity_of_maxwell

by Lucas · Oct 9, 2026 · Mathlib 0df444a (Lean v4.33.1)

continuity-equationmathematical-physics

Let H,D,J:R×R3→R3\mathbf H,\mathbf D,\mathbf J:\mathbb R\times\mathbb R^3\to\mathbb R^3H,D,J:R×R3→R3 and ρ:R×R3→R\rho:\mathbb R\times\mathbb R^3\to\mathbb Rρ:R×R3→R be time-dependent fields. Assume that H(t,⋅)\mathbf H(t,\cdot)H(t,⋅) is C2C^2C2 for every ttt and that D\mathbf DD is C2C^2C2 jointly in (t,x)(t,x)(t,x). Suppose Ampère's law with Maxwell's correction and Gauss's law hold everywhere:

∇×H=J+∂D∂t,∇⋅D=ρ.\nabla\times\mathbf H=\mathbf J+\frac{\partial\mathbf D}{\partial t},\qquad \nabla\cdot\mathbf D=\rho .∇×H=J+∂t∂D​,∇⋅D=ρ.

Then the continuity equation for electric charge holds everywhere:

∇⋅J+∂ρ∂t=0.\nabla\cdot\mathbf J+\frac{\partial\rho}{\partial t}=0 .∇⋅J+∂t∂ρ​=0.

This is the statement that charge conservation is an automatic consequence of Maxwell's equations.

Preamble
import Mathlib
import Definitions.Def_ContinuityEqWiki_Defs
Formal statement
namespace ContinuityEqWiki

theorem charge_continuity_of_maxwell (H D J : ℝ → Space → Space) (ρ : ℝ → Space → ℝ)
    (hH : ∀ t, ContDiff ℝ 2 (H t)) (hD : ContDiff ℝ 2 (Function.uncurry D))
    (ampere : ∀ t x, curl (H t) x = J t x + timeDeriv D t x)
    (gauss : ∀ t x, div (D t) x = ρ t x) :
    ∀ t x, div (J t) x + timeDeriv ρ t x = 0 := by sorry

end ContinuityEqWiki
Source
Wikipedia, "Continuity equation", revision oldid=1378634825, https://en.wikipedia.org/w/index.php?title=Continuity_equation&oldid=1378634825, section "Electromagnetism", box "Consistency with Maxwell's equations"
Read-back

What the Lean code literally says, in plain math · Aristotle (Harmonic) - drafting agent, non-blind read-back

Non-blind read-back — not independent testimony. This read-back was written by the same agent (Aristotle, by Harmonic) that drafted the Lean statement it describes, at the explicit request of the proposal owner. Its author knew the source text and the intended meaning while writing it, so it must not be mistaken for a blind, independent audit. Reviewers should compare the Lean code against the source themselves.

Let H,D,J\mathbf H,\mathbf D,\mathbf JH,D,J be arbitrary maps R×R3→R3\mathbb R\times\mathbb R^3\to\mathbb R^3R×R3→R3 and ρ\rhoρ an arbitrary map R×R3→R\mathbb R\times\mathbb R^3\to\mathbb RR×R3→R (written f(t,x)f(t,x)f(t,x)). Assume:

  1. for every ttt, x↦H(t,x)x\mapsto\mathbf H(t,x)x↦H(t,x) is C2C^2C2 on R3\mathbb R^3R3;
  2. (t,x)↦D(t,x)(t,x)\mapsto\mathbf D(t,x)(t,x)↦D(t,x) is C2C^2C2 on R×R3\mathbb R\times\mathbb R^3R×R3;
  3. for all t,xt,xt,x: ∇×H(t,⋅)(x)=J(t,x)+∂tD(t,x)\nabla\times\mathbf H(t,\cdot)(x)=\mathbf J(t,x)+\partial_t\mathbf D(t,x)∇×H(t,⋅)(x)=J(t,x)+∂t​D(t,x), where ∂tD(t,x)\partial_t\mathbf D(t,x)∂t​D(t,x) is the derivative of s↦D(s,x)s\mapsto\mathbf D(s,x)s↦D(s,x) at ttt;
  4. for all t,xt,xt,x: ∇⋅D(t,⋅)(x)=ρ(t,x)\nabla\cdot\mathbf D(t,\cdot)(x)=\rho(t,x)∇⋅D(t,⋅)(x)=ρ(t,x).

No regularity is assumed on J\mathbf JJ or ρ\rhoρ separately. Conclusion: for all t∈Rt\in\mathbb Rt∈R and x∈R3x\in\mathbb R^3x∈R3,

∇⋅J(t,⋅)(x)+∂tρ(t,x)=0,\nabla\cdot\mathbf J(t,\cdot)(x)+\partial_t\rho(t,x)=0,∇⋅J(t,⋅)(x)+∂t​ρ(t,x)=0,

with ∇⋅\nabla\cdot∇⋅ the sum of the three coordinate partial derivatives of the components and ∂tρ(t,x)\partial_t\rho(t,x)∂t​ρ(t,x) the derivative of s↦ρ(s,x)s\mapsto\rho(s,x)s↦ρ(s,x) at ttt.

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