Repairing an open periodic test set into a hitting set for all normalized progressions
ProvedOAI.Problem310.Auxiliary.repair_open_periodic_hittingmeasure-theoryoai-mathreal-analysistopology
Write for Lebesgue measure on , call 1-periodic if for all , and for , and a real sequence let
be the set of exceptional centers.
Theorem. Assume:
- is open and 1-periodic;
- , and every satisfies ;
- as ;
- satisfies ;
- .
Then there is an open, 1-periodic set with that is hit by every normalized progression:
This is the deterministic repair step of a probabilistic construction: if an open periodic test set has small density and its exceptional centers also have small density, then a genuine hitting set costs only more. For , the complement is a compact set of measure at least that contains no set of the form with and .
Formalization Note The index in the conclusion is any natural number ; it need not belong to . Measures and are extended nonnegative reals, and enters as ENNReal.ofReal ε.
Preamble
import Mathlib import Definitions.Def_DyadicAvoidance import Definitions.Def_OAI_MeasureTheory_DyadicAvoidance_PeriodicBasic import Definitions.Def_OAI_MeasureTheory_DyadicAvoidance_GridSeparation import Definitions.Def_OAI_MeasureTheory_DyadicAvoidance_FiniteTableModel import Definitions.Def_OAI_MeasureTheory_DyadicAvoidance_OrderedRouting import Definitions.Def_OAI_MeasureTheory_DyadicAvoidance_RoutingPath import Definitions.Def_OAI_MeasureTheory_DyadicAvoidance_CenterRouteExposure import Definitions.Def_OAI_MeasureTheory_DyadicAvoidance_ExceptionalCenters open OAI OAI.Problem310 OAI.Problem310.Auxiliary open Set Filter Topology open Set Filter Topology MeasureTheory
Formal statement
theorem OAI.Problem310.Auxiliary.repair_open_periodic_hitting
(B : Set ℝ) (hBo : IsOpen B)
(hBp : ∀ x : ℝ, x + 1 ∈ B ↔ x ∈ B)
(N : Set ℕ) (hN : ∀ n ∈ N, 1 ≤ n)
(a : ℕ → ℝ) (ha : Tendsto a atTop (𝓝 0))
(c : ENNReal)
(hbound : volume (B ∩ Icc (0 : ℝ) 1) +
volume (exceptionalCenters B N a ∩ Icc (0 : ℝ) 1) ≤ c)
(ε : ℝ) (hε : 0 < ε) :
∃ H : Set ℝ, IsOpen H ∧
(∀ x : ℝ, x + 1 ∈ H ↔ x ∈ H) ∧
volume (H ∩ Icc (0 : ℝ) 1) ≤ c + ENNReal.ofReal ε ∧
∀ x t : ℝ, t ∈ Icc (1 : ℝ) 2 →
∃ n : ℕ, 1 ≤ n ∧ x + t * a n ∈ H := by sorrySource