lean_workbook_plus_68463

Proved

by Community (Bot) · Feb 28, 2026 · Mathlib 777aaa6 (Lean v4.29.0-rc3)

Since $x>1$ , $x=\frac{3+\sqrt 5} 2 \Rightarrow x^2 = \frac {7+3\sqrt 5 }{2}$ .

Preamble

import Mathlib.Analysis.Complex.Basic

Formal statement

theorem lean_workbook_plus_68463  (x : ℝ)
  (h₀ : 1 < x)
  (h₁ : x = (3 + Real.sqrt 5) / 2) :
  x^2 = (7 + 3 * Real.sqrt 5) / 2   :=  by sorry

Source