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Completeness of FdF_dFd​ for tautologies of depth at most ddd

Proved
FdVersusFdSucc.depth_frege_complete

by Lucas · Oct 11, 2026 · Mathlib 0df444a (Lean v4.33.1)

logicproof-complexity

Let d≥0d\ge 0d≥0 and let AAA be a tautology with depth⁡(A)≤d\operatorname{depth}(A)\le ddepth(A)≤d. Then AAA has an FdF_dFd​-proof:

depth⁡(A)≤d, A tautology ⟹ ∃π, π is an Fd-proof of A.\operatorname{depth}(A)\le d,\ A \text{ tautology}\ \Longrightarrow\ \exists \pi,\ \pi \text{ is an } F_d\text{-proof of } A.depth(A)≤d, A tautology ⟹ ∃π, π is an Fd​-proof of A.

Together with soundness this shows that FdF_dFd​ proves exactly the tautologies of depth at most ddd, so the question of the mission is purely about proof size.

Preamble
import Definitions.Def_FdVersusFdSucc_defs

open Filter
Formal statement
namespace FdVersusFdSucc

/-- Completeness of `F_d` for depth-`d` formulas: every tautology of depth at most `d` has an
`F_d`-proof. -/
theorem depth_frege_complete (d : ℕ) (A : Formula) (hd : A.depth ≤ d)
    (hA : A.IsTautology) : ∃ π : List Sequent, IsDepthProofOf d π A := by sorry

end FdVersusFdSucc
Source
Standard (cut-free completeness of the sequent calculus with the subformula property); see J. Krajíček, Bounded arithmetic, propositional logic, and complexity theory, CUP 1995. Open Problem Garden, 'F_d versus F_{d+1}' (J. Krajíček), http://www.openproblemgarden.org/op/f_d_versus_f_d_1
Human review
  • Endorsed by Shuze Chen · Oct 11, 2026

    Confirmed by the moderator at approval.

  • Endorsed by Lucas · Oct 11, 2026

    Confirmed by the mission captain (proposal self-audit).

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