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Cook's Problem Statement, negative answer: P≠NP\mathbf{P} \neq \mathbf{NP}P=NP (Clay Millennium Prize Problem)

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PvsNP.P_ne_NP

by korbonits · Sep 8, 2026 · Mathlib 0df444a (Lean v4.33.1)

complexity-theorymillennium-prizenp-completenessp-vs-nppolynomial-timesatisfiabilityturing-machines

Cook's Problem Statement (p. 2) reads: Does P=NP\mathbf{P} = \mathbf{NP}P=NP? This theorem asserts the negative answer,

P≠NP:\mathbf{P} \neq \mathbf{NP}:P=NP:

the class of languages over {0,1}\{0,1\}{0,1} that are decided by some multi-stack machine within a polynomial number of steps is not the same as the class of languages that have a polynomial-time checking relation with polynomially bounded certificates. Since P⊆NP\mathbf{P} \subseteq \mathbf{NP}P⊆NP (Cook, p. 2; a milestone of this mission), the statement is equivalent to the existence of a language LLL with a polynomial-time checking relation RRR and an exponent kkk such that w∈L  ⟺  ∃y (∣y∣≤∣w∣k∧R(w,y))w \in L \iff \exists y\,(|y| \le |w|^k \wedge R(w,y))w∈L⟺∃y(∣y∣≤∣w∣k∧R(w,y)) for all www, but with no polynomial-time decision procedure.

Cook (p. 7): "Most complexity theorists believe that P≠NP\mathbf{P} \neq \mathbf{NP}P=NP." The Millennium Prize is offered for a proof of either answer; this theorem is the conjectured one. It is open: a proof would settle the Millennium Prize Problem and, by Cook's Proposition 1(c), show that none of the NP\mathbf{NP}NP-complete problems (Satisfiability, 3-SAT, Karp's 21 problems, and the hundreds catalogued since) has a polynomial-time algorithm. Its role in the mission is to fix in Lean the exact statement the prize asks about, so that the classical partial results (the milestones) are formalized against the same definitions.

Formalization Note P and NP are the sets of languages PvsNP.P, PvsNP.NP : Set (Language Bool) of the definition bundle, defined via Mathlib's Turing.TM2ComputableInPolyTime over the multi-stack machine model, which is polynomially equivalent to Turing machines. The statement is the inequality of these two sets. If P=NP\mathbf{P} = \mathbf{NP}P=NP is in fact true, this theorem is false; its negation is not an item of the mission.

Preamble
import Definitions.Def_PvsNP
import Mathlib
Formal statement
namespace PvsNP
theorem P_ne_NP : P ≠ NP := by sorry
end PvsNP
Source
S. Cook, The P versus NP problem, Clay Mathematics Institute Millennium Prize Problem description (2000), https://www.claymath.org/wp-content/uploads/2022/06/pvsnp.pdf, p. 2, 'Problem Statement. Does P = NP?', with the definitions of P and NP on the same page; p. 7, Section 3, 'Most complexity theorists believe that P ≠ NP'
Read-back

What the Lean code literally says, in plain math · claude-fable-5-1

Read-back: PvsNP.P_ne_NP

Statement. The declaration asserts

P≠NP,\mathbf{P} \neq \mathbf{NP},P=NP,

where P\mathbf{P}P and NP\mathbf{NP}NP are two specific sets of languages over the alphabet {false,true}\{\mathtt{false},\mathtt{true}\}{false,true}, defined in the accompanying bundle as spelled out below. A "language" here is simply an arbitrary set of finite lists of Booleans (no computability or decidability requirement is built into the notion of language itself). The statement P≠NP\mathbf{P} \neq \mathbf{NP}P=NP is the negation of set equality: it is not the case that every language in P\mathbf{P}P is in NP\mathbf{NP}NP and every language in NP\mathbf{NP}NP is in P\mathbf{P}P. Classically this is equivalent to: there is a language over {false,true}\{\mathtt{false},\mathtt{true}\}{false,true} lying in exactly one of the two sets. The declaration has no hypotheses, no free variables and no typeclass assumptions; the proof body is a placeholder (sorry), so nothing is proved — the read-back below describes only what is claimed.

Throughout, a string means a finite list www of Booleans; ∣w∣|w|∣w∣ denotes its length (the empty string is allowed, ∣w∣=0|w| = 0∣w∣=0).


The machine model used by both classes

Both classes are defined via a fixed notion "fff is computable in polynomial time by a stack machine", taken from Mathlib (Turing.TM2ComputableInPolyTime). Unfolded, "there exists a polynomial-time machine computing fff with input encoding eine_{\mathrm{in}}ein​ and output encoding eoute_{\mathrm{out}}eout​" means that the following data exist (the definitions below use it only as a proposition, i.e. only the existence of such data matters, not any particular choice):

  • A finite stack machine MMM consisting of:
    • a finite type KKK of stack indices with decidable equality, together with two distinguished indices k0k_0k0​ (input stack) and k1k_1k1​ (output stack), which are allowed to coincide;
    • for each k∈Kk \in Kk∈K a type Γk\Gamma_kΓk​ of symbols that may be stored on stack kkk; the only finiteness requirement on these is that Γk0\Gamma_{k_0}Γk0​​ is finite — the symbol types of the other stacks are arbitrary types (though Γk1\Gamma_{k_1}Γk1​​ is forced to be finite by the bijection with the output alphabet below);
    • a finite type Λ\LambdaΛ of program labels with a distinguished label main\mathrm{main}main;
    • a finite type σ\sigmaσ of internal states with a distinguished initial state s0s_0s0​;
    • a program m:Λ→Stmtm : \Lambda \to \mathrm{Stmt}m:Λ→Stmt, assigning to every label a statement. Statements are finite trees built from: push onto stack kkk a symbol computed from the current internal state by an arbitrary function σ→Γk\sigma \to \Gamma_kσ→Γk​; peek at the top of stack kkk and update the internal state by an arbitrary function σ→Option(Γk)→σ\sigma \to \mathrm{Option}(\Gamma_k) \to \sigmaσ→Option(Γk​)→σ; pop stack kkk and update the internal state likewise; load, applying an arbitrary function σ→σ\sigma \to \sigmaσ→σ; branch on an arbitrary predicate σ→Bool\sigma \to \mathrm{Bool}σ→Bool; goto a label chosen by an arbitrary function σ→Λ\sigma \to \Lambdaσ→Λ; and halt. (The functions inside statements are arbitrary set-theoretic functions; since σ\sigmaσ and Λ\LambdaΛ are finite this is unproblematic, but no restriction such as computability of these functions is imposed.)
  • A bijection ιin:Γk0≃Ain\iota_{\mathrm{in}} : \Gamma_{k_0} \simeq A_{\mathrm{in}}ιin​:Γk0​​≃Ain​ between the input-stack symbols and the input alphabet AinA_{\mathrm{in}}Ain​, and a bijection ιout:Γk1≃Aout\iota_{\mathrm{out}} : \Gamma_{k_1} \simeq A_{\mathrm{out}}ιout​:Γk1​​≃Aout​ between the output-stack symbols and the output alphabet AoutA_{\mathrm{out}}Aout​.
  • A polynomial ppp with natural-number coefficients (any element of N[X]\mathbb{N}[X]N[X], including constant polynomials and the zero polynomial).
  • A correctness-with-time-bound proof: for every input aaa, letting ℓ=ein(a)\ell = e_{\mathrm{in}}(a)ℓ=ein​(a) be the encoded input (a list over AinA_{\mathrm{in}}Ain​), the machine started in the initial configuration — current label main\mathrm{main}main, internal state s0s_0s0​, stack k0k_0k0​ holding ιin−1\iota_{\mathrm{in}}^{-1}ιin−1​ applied elementwise to ℓ\ellℓ (first list element on top), all other stacks empty — reaches, after some number sss of steps with
s  ≤  p(∣ℓ∣)  =  p(∣ein(a)∣),s \;\le\; p\bigl(|\ell|\bigr) \;=\; p\bigl(|e_{\mathrm{in}}(a)|\bigr),s≤p(∣ℓ∣)=p(∣ein​(a)∣),

exactly the halting configuration for the output: current label "halted", internal state equal to the initial state s0s_0s0​ again, stack k1k_1k1​ holding ιout−1\iota_{\mathrm{out}}^{-1}ιout−1​ applied elementwise to eout(f(a))e_{\mathrm{out}}(f(a))eout​(f(a)), and every other stack empty (in particular, if k0≠k1k_0 \neq k_1k0​=k1​ the input stack must have been emptied). A step means one application of the step function, which executes an entire statement tree from a label up to and including its terminal goto or halt; the many pushes/pops inside a single statement count as one step. "Reaches after sss steps" is the exact equality of the sss-fold iterate of the step function (in the option monad) with the halting configuration; because a halted configuration has no successor, sss is exactly the number of steps at which the machine halts.

Two encodings from Mathlib are used:

  • encodeBool:Bool→strings\mathrm{encodeBool} : \mathrm{Bool} \to \text{strings}encodeBool:Bool→strings, sending b↦[b]b \mapsto [b]b↦[b] (the one-element list).
  • The identity encoding on strings (input alphabet {false,true}\{\mathtt{false},\mathtt{true}\}{false,true}; the encoded input is the string itself, so the time bound is p(∣w∣)p(|w|)p(∣w∣)).

The bundle adds one encoding of its own:

  • encodePair:strings×strings→lists over Bool⊕Bool\mathrm{encodePair} : \text{strings} \times \text{strings} \to \text{lists over } \mathrm{Bool} \oplus \mathrm{Bool}encodePair:strings×strings→lists over Bool⊕Bool, with
encodePair(x,y)  =  [ inl(x1),…,inl(x∣x∣), inr(y1),…,inr(y∣y∣) ],\mathrm{encodePair}(x, y) \;=\; [\,\mathrm{inl}(x_1), \dots, \mathrm{inl}(x_{|x|}),\ \mathrm{inr}(y_1), \dots, \mathrm{inr}(y_{|y|})\,],encodePair(x,y)=[inl(x1​),…,inl(x∣x∣​), inr(y1​),…,inr(y∣y∣​)],

i.e. the symbols of xxx tagged "left" followed by the symbols of yyy tagged "right"; the input alphabet is the four-element type Bool⊕Bool\mathrm{Bool} \oplus \mathrm{Bool}Bool⊕Bool and ∣encodePair(x,y)∣=∣x∣+∣y∣|\mathrm{encodePair}(x,y)| = |x| + |y|∣encodePair(x,y)∣=∣x∣+∣y∣.


The class P\mathbf{P}P

A language LLL (a set of strings) belongs to P\mathbf{P}P iff there exists a total function χ:strings→Bool\chi : \text{strings} \to \mathrm{Bool}χ:strings→Bool such that

  1. χ\chiχ is a polynomial-time decider: there exists a finite stack machine, in the sense above, with input encoding the identity on strings (input alphabet {false,true}\{\mathtt{false},\mathtt{true}\}{false,true}), output encoding encodeBool\mathrm{encodeBool}encodeBool (output alphabet {false,true}\{\mathtt{false},\mathtt{true}\}{false,true}), and some polynomial p∈N[X]p \in \mathbb{N}[X]p∈N[X], which for every string www, started on www, halts within p(∣w∣)p(|w|)p(∣w∣) steps in the halting configuration whose output stack holds exactly the one-symbol list [χ(w)][\chi(w)][χ(w)] and whose other stacks are empty; and
  2. for every string www:   w∈L  ⟺  χ(w)=true\;w \in L \iff \chi(w) = \mathtt{true}w∈L⟺χ(w)=true.

The class NP\mathbf{NP}NP

A language LLL belongs to NP\mathbf{NP}NP iff there exist a total function R:strings×strings→BoolR : \text{strings} \times \text{strings} \to \mathrm{Bool}R:strings×strings→Bool and a natural number k∈Nk \in \mathbb{N}k∈N (with k=0k = 0k=0 allowed) such that

  1. RRR is a polynomial-time checker: there exists a finite stack machine, in the sense above, with input encoding encodePair\mathrm{encodePair}encodePair (input alphabet Bool⊕Bool\mathrm{Bool} \oplus \mathrm{Bool}Bool⊕Bool), output encoding encodeBool\mathrm{encodeBool}encodeBool, and some polynomial p∈N[X]p \in \mathbb{N}[X]p∈N[X], which for every pair (w,y)(w, y)(w,y), started on encodePair(w,y)\mathrm{encodePair}(w,y)encodePair(w,y), halts within p(∣w∣+∣y∣)p(|w| + |y|)p(∣w∣+∣y∣) steps in the halting configuration whose output stack holds exactly [R(w,y)][R(w,y)][R(w,y)] and whose other stacks are empty; and
  2. for every string www:
w∈L  ⟺  ∃ y∈strings,  ∣y∣≤∣w∣k ∧ R(w,y)=true.w \in L \iff \exists\, y \in \text{strings},\ \ |y| \le |w|^{k} \ \wedge\ R(w, y) = \mathtt{true}.w∈L⟺∃y∈strings,  ∣y∣≤∣w∣k ∧ R(w,y)=true.

Edge cases made explicit by the quantifiers: the exponent kkk ranges over all natural numbers including 000, in which case the bound reads ∣y∣≤1|y| \le 1∣y∣≤1 for every www (with 00=10^0 = 100=1, so this also applies to the empty string); for k≥1k \ge 1k≥1 and www the empty string the bound is ∣y∣≤0|y| \le 0∣y∣≤0, so only the empty certificate is admissible. The certificate bound is ≤\le≤, not <<<. The polynomial time bound for the checker is measured in ∣w∣+∣y∣|w| + |y|∣w∣+∣y∣, not in ∣w∣|w|∣w∣ alone. There is no requirement that RRR or χ\chiχ be anything beyond a total Boolean-valued function that some machine computes within the stated bound.


What the theorem claims, assembled

Let P\mathbf{P}P be the set of all languages L⊆{false,true}∗L \subseteq \{\mathtt{false},\mathtt{true}\}^{*}L⊆{false,true}∗ for which some Boolean-valued function χ\chiχ on strings, computed by a finite stack machine (as specified above, with identity input encoding and one-symbol output) within a polynomial number of steps in the input length, satisfies w∈L  ⟺  χ(w)=truew \in L \iff \chi(w) = \mathtt{true}w∈L⟺χ(w)=true for all www. Let NP\mathbf{NP}NP be the set of all languages LLL for which some Boolean-valued function RRR on pairs of strings, computed by a finite stack machine (with the tagged-concatenation input encoding encodePair\mathrm{encodePair}encodePair and one-symbol output) within a polynomial number of steps in ∣w∣+∣y∣|w| + |y|∣w∣+∣y∣, together with some k∈Nk \in \mathbb{N}k∈N, satisfies w∈L  ⟺  ∃y (∣y∣≤∣w∣k∧R(w,y)=true)w \in L \iff \exists y\,(|y| \le |w|^k \wedge R(w,y) = \mathtt{true})w∈L⟺∃y(∣y∣≤∣w∣k∧R(w,y)=true) for all www. The declaration P_ne_NP asserts

P≠NP\mathbf{P} \neq \mathbf{NP}P=NP

as an inequality of sets of languages, with no further hypotheses. It does not assert which inclusion fails, does not assert P⊆NP\mathbf{P} \subseteq \mathbf{NP}P⊆NP, and does not exhibit any witness language; it also makes no reference to the other notions in the bundle (reductions, NP\mathbf{NP}NP-completeness, E\mathbf{E}E, CNF formulas, SAT\mathrm{SAT}SAT, 3SAT3\mathrm{SAT}3SAT), none of which occur in the statement.

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