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Nielsen Theorem 1: N<(d+1)4kN < (d+1)^{4^k}N<(d+1)4k for odd n/dn/dn/d-perfect NNN

Proved
OddPerfectNumber.nielsen_theorem1

by curiyu · Sep 8, 2026 · Mathlib 0df444a (Lean v4.33.1)

divisor-sumsnumber-theoryopen-problemperfect-numbers

This is Theorem 1 of Nielsen 2003 (pages 4-7), the general upper bound from which the odd-perfect milestone follows.

Let NNN be odd and n/dn/dn/d-perfect with n,dn, dn,d positive, i.e. σ(N) d=n N\sigma(N)\,d = n\,Nσ(N)d=nN where σ\sigmaσ is the sum-of-divisors function, and let kkk be the number of distinct prime divisors of NNN. Then

N<(d+1)4k.N < (d+1)^{4^{k}}.N<(d+1)4k.

The published proof strengthens Heath-Brown's algorithm: starting from any prime set SSS, Cases 1-2 build a disjoint extension S′S'S′ giving inequalities (1)-(2), then a subset S′′⊆S∪S′S'' \subseteq S \cup S'S′′⊆S∪S′ giving (3)-(4); a long calculation yields the key estimate (5), which replaces inequality (iv) of Heath-Brown's Lemma 2. The Heath-Brown induction (p. 196) with (5) in place of (iv) gives the bound. The odd-perfect corollary (n=2n = 2n=2, d=1d = 1d=1) is N<24kN < 2^{4^{k}}N<24k.

Formalization Note The n/dn/dn/d-perfect hypothesis is stated cross-multiplied in N\mathbb{N}N as ArithmeticFunction.sigma 1 N * d = n * N, and kkk is N.primeFactors.card.

Preamble
import Mathlib
Formal statement
namespace OddPerfectNumber

theorem nielsen_theorem1 (N n d : ℕ) (hn : 0 < n) (hd : 0 < d) (hodd : Odd N)
    (hperf : ArithmeticFunction.sigma 1 N * d = n * N) :
    N < (d + 1) ^ (4 ^ N.primeFactors.card) := by
  sorry

end OddPerfectNumber
Source
P. P. Nielsen, An upper bound for odd perfect numbers, INTEGERS 3 (2003), #A14, Theorem 1, pp. 4-7, https://emis.muni.cz/journals/INTEGERS/papers/d14/d14.pdf

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