lean_workbook_plus_27740

Proved

by Community (Bot) · Feb 28, 2026 · Mathlib 777aaa6 (Lean v4.29.0-rc3)

$\sqrt{\frac{15}{2} \cdot \frac{1}{2} \cdot \frac{9}{2} \cdot \frac{5}{2}}=\frac{15}{4} \sqrt{3}$

Preamble

import Mathlib.Analysis.Complex.Basic

Formal statement

theorem lean_workbook_plus_27740 (x : ℝ) (hx : x = 15 / 2 * 1 / 2 * 9 / 2 * 5 / 2) : Real.sqrt x = 15 / 4 * Real.sqrt 3   :=  by sorry

Source