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Two right-handed neutrinos: the seesaw mass matrix has rank ≤2\le 2≤2 and a massless state

Proved
NewMinimalStandardModel.seesawMassMatrix_rank_le_two

by Lucas · Oct 4, 2026 · Mathlib 0df444a (Lean v4.33.1)

linear-algebramathematical-physicsneutrino-physics

Let v∈Rv\in\mathbb Rv∈R, let hνh_\nuhν​ be a complex 2×32\times32×3 Yukawa matrix and let M1,M2>0M_1,M_2>0M1​,M2​>0 be the right-handed-neutrino masses. Let mD=hνv/2m_D = h_\nu v/\sqrt2mD​=hν​v/2​ and let

mν=− mDTdiag⁡(M1,M2)−1mDm_\nu = -\,m_D^{\mathsf T}\operatorname{diag}(M_1,M_2)^{-1}m_Dmν​=−mDT​diag(M1​,M2​)−1mD​

be the seesaw light-neutrino mass matrix. Then

  1. rank⁡mν≤2\operatorname{rank} m_\nu \le 2rankmν​≤2, and
  2. some physical mass of mνm_\numν​ vanishes: σi(mν)=0\sigma_i(m_\nu)=0σi​(mν​)=0 for some iii, where σi(mν)=λi(mν†mν)\sigma_i(m_\nu)=\sqrt{\lambda_i(m_\nu^\dagger m_\nu)}σi​(mν​)=λi​(mν†​mν​)​.

This is the statement "Because the left-handed neutrino Majorana mass matrix has rank two, there is one massless state" (p. 119).

Preamble
import Mathlib
import Definitions.Def_NewMinimalStandardModel_Defs
Formal statement
namespace NewMinimalStandardModel

theorem seesawMassMatrix_rank_le_two (v : ℝ) (hν : Matrix (Fin 2) (Fin 3) ℂ) (M : Fin 2 → ℝ)
    (hM : ∀ α, 0 < M α) :
    (seesawMassMatrix v hν M).rank ≤ 2 ∧
      ∃ i, majoranaMasses (seesawMassMatrix v hν M) i = 0 := by sorry

end NewMinimalStandardModel
Source
H. Davoudiasl, R. Kitano, T. Li, H. Murayama, The new Minimal Standard Model, Phys. Lett. B 609 (2005) 117-123, https://doi.org/10.1016/j.physletb.2005.01.026, p. 119, right column (discussion after Eq. (4))
Read-back

What the Lean code literally says, in plain math · Aristotle (Harmonic) - same agent that drafted the statements; NON-BLIND, not an independent auditor

NON-BLIND READ-BACK — NOT INDEPENDENT TESTIMONY. This read-back was written by the same agent that drafted the Lean statement, with full knowledge of the source paper and of the intended meaning. It was not produced by a blind, independent auditor and must not be treated as independent evidence of faithfulness. Reviewers should compare the Lean code against the source themselves.

For every real number vvv, every complex 2×32\times32×3 matrix hνh_\nuhν​, and every pair of real numbers M1,M2M_1, M_2M1​,M2​ with M1>0M_1>0M1​>0 and M2>0M_2>0M2​>0, consider the complex 3×33\times33×3 matrix

mν=−(v2hν)Tdiag⁡(M1,M2)−1(v2hν)m_\nu = -\Big(\tfrac{v}{\sqrt2}h_\nu\Big)^{\mathsf T}\operatorname{diag}(M_1,M_2)^{-1}\Big(\tfrac{v}{\sqrt2}h_\nu\Big)mν​=−(2​v​hν​)Tdiag(M1​,M2​)−1(2​v​hν​)

(plain transpose; Mathlib matrix inverse, which here is the genuine inverse since M1,M2≠0M_1,M_2\neq0M1​,M2​=0). The theorem asserts two things: (1) the rank of mνm_\numν​ (as a matrix over C\mathbb CC) is at most 222; and (2) there exists an index i∈{1,2,3}i\in\{1,2,3\}i∈{1,2,3} such that λi=0\sqrt{\lambda_i}=0λi​​=0, where λ1,λ2,λ3\lambda_1,\lambda_2,\lambda_3λ1​,λ2​,λ3​ are the eigenvalues of the Hermitian matrix mν†mνm_\nu^\dagger m_\numν†​mν​ as enumerated by Mathlib's spectral theorem. No hypothesis is placed on vvv (it may be 000, in which case mν=0m_\nu=0mν​=0) or on hνh_\nuhν​.

Human review
  • Endorsed by Shuze Chen · Oct 8, 2026

    Confirmed by the moderator at approval.

  • Endorsed by Lucas · Oct 8, 2026

    Confirmed by the mission captain (proposal self-audit).

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