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The logarithmic-integral model diverges

Proved
HardyLittlewood.tuple_integral_diverges

by Lucas · Oct 19, 2026 · Mathlib 0df444a (Lean v4.33.1)

asymptoticsnumbertheoryrealanalysis

For every multiplicity k + 1, the model integral of the first Hardy–Littlewood conjecture grows without bound: the integral of 1/(log t)^(k+1) over [2, n] tends to +∞ as n → ∞. This is the divergence that makes the conjecture's conclusion an infinitude statement: a positive constant against a diverging model forces the count to grow.

Preamble
import Mathlib
import Definitions.Def_HardyLittlewood_constellation
import Definitions.Def_HardyLittlewood_counting
import Definitions.Def_HardyLittlewood_series
Formal statement
namespace HardyLittlewood

/-- The model integral of the first Hardy–Littlewood conjecture diverges: for
every multiplicity k + 1, the integral of 1 / (log t)^(k+1) over [2, n] grows
without bound as n → ∞. -/
theorem tuple_integral_diverges (k : ℕ) :
    Filter.Tendsto (fun n => ∫ t in (2:ℝ)..(n:ℝ), 1 / (Real.log t) ^ (k + 1))
      Filter.atTop Filter.atTop := by
  sorry

end HardyLittlewood
Source
Hardy and Littlewood (1923), Acta Math. 44, the logarithmic-integral model of the prime k-tuple asymptotic
Read-back

What the Lean code literally says, in plain math · glm-5-latest-short

The statement says: for every natural number k, the function sending each natural number n to the integral from 2 to n of the function t ↦ 1 divided by the (k+1)-th power of the natural logarithm of t tends to positive infinity along the filter at top; that is, for every real bound there is an index beyond which all values of the function exceed the bound.

Human review
  • Endorsed by Shuze Chen · Oct 20, 2026

    Confirmed by the moderator at approval.

  • Endorsed by Lucas · Oct 20, 2026

    Confirmed by the mission captain (proposal self-audit).

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