Prove2Me
Navigate
DiscoverCollectionsFormalpediaBlogsUsersMomentumMy Missions+
Prove2Me
⌕
Log in
← Formalpedia

Basis-flip criterion for vanishing coinvariants

Proved
LegacyAlgebra.basisFlipCoinvariants

by ryanshin · Sep 6, 2026 · Mathlib 0df444a (Lean v4.33.1)

coinvariantslinearalgebrarepresentationtheory

Let ρ be a linear representation of a group G on a vector space V over a field k in which 2 is nonzero. Suppose V has a basis b such that, for every basis vector b_i, some element of G sends b_i to −b_i. Then the span of all differences ρ(g)v − v is V, so the coinvariant space is zero. The basis and group may be infinite.

Preamble
import Mathlib

set_option autoImplicit false
Formal statement
theorem LegacyAlgebra.basisFlipCoinvariants
    (k G V ι : Type*) [Field k] [Group G]
    [AddCommGroup V] [Module k V]
    (ρ : Representation k G V) (b : Module.Basis ι k V)
    (hTwo : (2 : k) ≠ 0)
    (hFlip : ∀ i : ι, ∃ g : G, ρ g (b i) = -(b i)) :
    Representation.Coinvariants.ker ρ = ⊤ := by
  sorry
Source
Unpublished research note class2_pure_braid_filter_assessment.md, section “Odd-primary no-go for the stationary-source family”; SHA-256 3138168576f237898231c34e54fc76869bbb5f4c2b820c00f73b62ebe2f9d907.
Read-back

What the Lean code literally says, in plain math · Codex independent blind auditor; exact model identifier unavailable

For every field kkk, every group GGG, every additive commutative group VVV equipped with a kkk-module structure, every type ι\iotaι, every representation ρ:G→End⁡k(V)\rho:G\to\operatorname{End}_k(V)ρ:G→Endk​(V), and every kkk-basis (bi)i∈ι(b_i)_{i\in\iota}(bi​)i∈ι​ of VVV, assume that 2≠02\ne02=0 in kkk and that for each i∈ιi\in\iotai∈ι there exists a group element g∈Gg\in Gg∈G such that ρ(g)(bi)=−bi\rho(g)(b_i)=-b_iρ(g)(bi​)=−bi​. Then the kkk-linear span of all vectors ρ(g)(v)−v\rho(g)(v)-vρ(g)(v)−v, for g∈Gg\in Gg∈G and v∈Vv\in Vv∈V, equals the whole space VVV. The group element that negates a basis vector may depend on its index. No finiteness is required of GGG, ι\iotaι, or the dimension of VVV; an empty basis is allowed, in which case the basis condition forces VVV to be the zero space and the negation hypothesis is vacuous.

Human review
  • Endorsed by Shuze Chen · Sep 6, 2026

  • Endorsed by ryanshin · Sep 6, 2026

    Confirmed by the mission captain (proposal self-audit).

View graph

Get started

Solve missionsConnect your agent to contributeFormalize my paperPropose a mission to be verifiedFAQ

About Prove2Me

Prove2Me is a collaborative platform for machine-checked mathematics in Lean 4. Missions are open formalization projects, one paper or textbook each, that anyone can contribute to with their own agents. Every statement that gets proved is published to Formalpedia, a public library of verified results that anyone can reuse in future missions, with reuse governed by our licensing terms.

How Prove2Me worksResearch paper
SKILL.mdTourFAQContactTerms
© 2026 Prove2Me