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Rubinstein’s exact quadratic separation

Proved
SensitivityCampaign.rubinstein_bounds

by marwahaha · Oct 16, 2026 · Mathlib 0df444a (Lean v4.33.1)

block-sensitivityboolean-functionssensitivity

For each integer m ≥ 1, there exists a total Boolean function f on (2m)² bits with s(f)=2m and bs(f)=2m². Both are global maxima over all inputs.

Preamble
import Mathlib
import Definitions.Def_SensitivityCampaign
Formal statement
namespace SensitivityCampaign
theorem rubinstein_bounds (m : ℕ) (hm : 1 ≤ m) :
    ∃ f : (Fin ((2 * m) ^ 2) → Bool) → Bool,
      OAI.Paper320.sensitivity f = 2 * m ∧
      OAI.Paper320.blockSensitivity f = 2 * m ^ 2 := by sorry
end SensitivityCampaign
Source
David Rubinstein, Sensitivity vs. block sensitivity of Boolean functions, Combinatorica 15 (1995), 297–299, https://doi.org/10.1007/BF01200762; Theorem 1 recalled in https://arxiv.org/abs/1008.0521
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What the Lean code literally says, in plain math · GPT-6 (independent blind auditor; exact runtime identifier unavailable)

For every natural number mmm with m≥1m\ge 1m≥1, there exists a Boolean function f:{0,1}(2m)2→{0,1}f:\{0,1\}^{(2m)^2}\to\{0,1\}f:{0,1}(2m)2→{0,1} with the following two exact equalities. For an input xxx and a set BBB of coordinate indices, let xBx^BxB be the input obtained by complementing exactly the coordinates in BBB. Define s(f)s(f)s(f) to be the maximum, over all inputs xxx, of the number of indices iii for which f(x{i})≠f(x)f(x^{\{i\}})\ne f(x)f(x{i})=f(x). Define b(f)b(f)b(f) to be the maximum, over all inputs xxx, of the largest cardinality of a family of distinct, pairwise disjoint, nonempty sets BBB of coordinate indices such that f(xB)≠f(x)f(x^B)\ne f(x)f(xB)=f(x) for every member BBB of the family; the empty family is allowed and has cardinality zero. Then s(f)=2ms(f)=2ms(f)=2m and b(f)=2m2b(f)=2m^2b(f)=2m2, where the latter means 2⋅(m2)2\cdot(m^2)2⋅(m2), whereas the number of coordinates is (2m)2=4m2(2m)^2=4m^2(2m)2=4m2. Both maxima are taken over all Boolean inputs independently; the statement does not require the same input to attain them. The function may depend on mmm and is not asserted to be unique. The case m=1m=1m=1 is included, and m=0m=0m=0 is excluded by the hypothesis.

Human review
  • Endorsed by Shuze Chen · Oct 16, 2026

    Confirmed by the moderator at approval.

  • Endorsed by marwahaha · Oct 16, 2026

    Confirmed by the mission captain (proposal self-audit).

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