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Termination of label correcting (Prop. 2.3.1)

Proved
BertsekasDP.label_correcting_terminates

by Shuze Chen · Sep 6, 2026 · Mathlib 0df444a (Lean v4.33.1)

labelcorrectingtermination

Proposition 2.3.1 (termination of the label correcting method). Consider the shortest path problem of §2.3 on a finite directed graph, and assume that every cycle has nonnegative length — formally, that every closed walk lll from a node vvv back to itself satisfies

ℓ(l)  ≥  0.\ell(l) \;\ge\; 0 .ℓ(l)≥0.

Then the label correcting algorithm terminates: there is no infinite sequence of states σ0,σ1,σ2,…\sigma_0, \sigma_1, \sigma_2, \dotsσ0​,σ1​,σ2​,… with σ0\sigma_0σ0​ the initial state and σk+1\sigma_{k+1}σk+1​ obtained from σk\sigma_kσk​ by one iteration of the algorithm.

Termination is the half of Prop. 2.3.1 that survives under the weaker hypothesis: it needs only that cycles do not pay, whereas the correctness half needs nonnegative arcs. The argument in the source is a counting one — each time a node enters OPEN\mathrm{OPEN}OPEN its label strictly decreases to the length of some walk from the origin, and below any given bound there are only finitely many such lengths.

Formalization Note The claim is the negation of the existence of an infinite run starting at the initial state; it does not bound the number of iterations, and it says nothing about runs started elsewhere. Because a step requires a node in OPEN\mathrm{OPEN}OPEN, an infinite run would in particular keep OPEN\mathrm{OPEN}OPEN nonempty forever.

Preamble
import Mathlib
import Definitions.Def_BertsekasSPGraph
import Definitions.Def_BertsekasLCState
Formal statement
namespace BertsekasDP

theorem label_correcting_terminates {V : Type} [Fintype V] [DecidableEq V]
    (G : BertsekasSPGraph V)
    (hcyc : ∀ v l, BertsekasIsWalkFrom G v v l → 0 ≤ BertsekasWalkLength G l) :
    ¬ ∃ seq : ℕ → BertsekasLCState V,
        seq 0 = BertsekasLCInit G ∧
        ∀ k, BertsekasLCStep G (seq k) (seq (k + 1)) := by sorry

end BertsekasDP
Source
D. P. Bertsekas, Dynamic Programming and Optimal Control, Vol. I, 3rd ed., Athena Scientific, 2005, Proposition 2.3.1 (termination part)
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What the Lean code literally says, in plain math · claude-fable-5

Let VVV be any finite type with decidable equality and GGG any BertsekasSPGraph on VVV. Assume (hcyc): for every vertex vvv and every list lll with IsWalkFrom(G,v,v,l)\mathrm{IsWalkFrom}(G, v, v, l)IsWalkFrom(G,v,v,l) (nonempty, consecutive pairs are arcs, first and last element both vvv), the walk length ∑ℓ\sum \ell∑ℓ over consecutive pairs is ≥0\ge 0≥0 — i.e. no closed walk of GGG has negative length. Then the theorem asserts: there is no infinite run of the algorithm, i.e. there exists no function σ∙:N→\sigma_\bullet : \mathbb{N} \toσ∙​:N→ states such that

σ0=Init(G)and∀k∈N, Step(G,σk,σk+1),\sigma_0 = \mathrm{Init}(G) \quad\text{and}\quad \forall k \in \mathbb{N},\ \mathrm{Step}(G, \sigma_k, \sigma_{k+1}),σ0​=Init(G)and∀k∈N, Step(G,σk​,σk+1​),

where Init\mathrm{Init}Init and Step\mathrm{Step}Step are as expanded above (Step\mathrm{Step}Step requires at each stage a vertex in the current open set, so an infinite run in particular requires every σk\sigma_kσk​ to have a nonempty open set). The statement is a plain negation of existence of such a sequence starting at the initial state; it says nothing about runs starting from other states, and nothing about how many steps a finite run may take. The proof is left as sorry.

Human review
  • Endorsed by Community (Bot) · Sep 6, 2026

  • Endorsed by Shuze Chen · Sep 6, 2026

    Confirmed by the mission captain (proposal self-audit).

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