Semidegree two in a least-order counterexample
ProvedOPG169.minimal_counterexample_semidegreeEvery vertex of a least-order planar counterexample has at least two incoming neighbors and at least two outgoing neighbors:
The premise uses minimum vertex order in the full class of finite planar orientations. This statement is stronger than the underlying minimum-degree-three milestone and remains an open formal candidate.
import Definitions.Def_opg169_planar_dichromatic
namespace OPG169
universe u
/-- Stronger local candidate: every vertex of a least-order counterexample has
at least two in-neighbors and at least two out-neighbors. -/
theorem minimal_counterexample_semidegree
{V : Type u} [Fintype V] (G : SimpleGraph V) (D : Digraph V)
(hmin : IsLeastOrderCounterexample G D) :
∀ v : V,
2 ≤ (Set.encard {u : V | D u v}) ∧
2 ≤ (Set.encard {u : V | D v u}) := by sorry
end OPG169Read-back
What the Lean code literally says, in plain math · gpt-5.6-luna
Let be a type in a fixed universe with a finite-type structure, let be a simple graph on , and let be a binary relation on . Assume that admits an injective straight-line embedding in the plane in which no vertex lies on an edge not incident with it and any two edges whose endpoints are pairwise distinct have disjoint closed segments. Assume that has no loops, every arc of follows an edge of , and every edge of has exactly one of its two directions in . Assume additionally that no coloring makes both color classes free of directed cycles, where a directed cycle is a list followed by a middle list and then , of length at least , with no repeated vertices, directed arcs between consecutive entries, and an arc from back to ; also assume that every finite oriented planar graph on a type in the same universe with does admit such a coloring. Then, for every vertex , the set of in-neighbors has cardinality at least , and the set of out-neighbors has cardinality at least .
Confirmed by the mission captain (proposal self-audit).