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Shifting the parameter of the second loop does not change the Gauss linking integral

Proved
HryniewiczCriterion.gaussLinkingIntegral_comp_add_right

by Mazecto · Oct 9, 2026 · Mathlib 0df444a (Lean v4.33.1)

geometry-topologysymplectic-geometry

Let γ2:R→R4\gamma_2:\mathbb{R}\to\mathbb{R}^4γ2​:R→R4 be 111-periodic, let γ1\gamma_1γ1​ be any loop, and let c∈Rc\in\mathbb{R}c∈R. Then

GaussN(γ1, t↦γ2(t+c))=GaussN(γ1,γ2).\mathrm{Gauss}_N\big(\gamma_1,\ t\mapsto\gamma_2(t+c)\big)=\mathrm{Gauss}_N(\gamma_1,\gamma_2).GaussN​(γ1​, t↦γ2​(t+c))=GaussN​(γ1​,γ2​).

GaussN(γ1,γ2)\mathrm{Gauss}_N(\gamma_1,\gamma_2)GaussN​(γ1​,γ2​) denotes gaussLinkingIntegral N γ₁ γ₂, the Gauss double integral 14π∫01 ⁣∫01vol⁡(A′(s),B′(t),A(s)−B(t))∣A(s)−B(t)∣3 dt ds\frac1{4\pi}\int_0^1\!\int_0^1\frac{\operatorname{vol}(A'(s),B'(t),A(s)-B(t))}{|A(s)-B(t)|^3}\,dt\,ds4π1​∫01​∫01​∣A(s)−B(t)∣3vol(A′(s),B′(t),A(s)−B(t))​dtds of the stereographic images A=σN∘γ1A=\sigma_N\circ\gamma_1A=σN​∘γ1​, B=σN∘γ2B=\sigma_N\circ\gamma_2B=σN​∘γ2​ from the pole NNN.

The inner integrand is 111-periodic in ttt, so an integral over any interval of length 111 gives the same value. No regularity or disjointness hypothesis is needed: the identity holds for the defining expression as it stands.

Preamble
import Definitions.Def_HryniewiczCriterion_GlobalSection
import Definitions.Def_HryniewiczCriterion_SelfLinking

open HryniewiczCriterion
Formal statement
theorem HryniewiczCriterion.gaussLinkingIntegral_comp_add_right (N : R4) (γ₁ γ₂ : ℝ → R4)
    (hper₂ : ∀ t, γ₂ (t + 1) = γ₂ t) (c : ℝ) :
    gaussLinkingIntegral N γ₁ (fun t => γ₂ (t + c)) = gaussLinkingIntegral N γ₁ γ₂ := by sorry
Source
Elementary (periodicity of the Gauss integrand); used to move a crossing to t=0t=0t=0 in U. Hryniewicz, arXiv:1105.2077, Lemma 3.12

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