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Solutions of linear Cauchy–Riemann equations have no zeros near infinity

Proved
FiniteEnergyPlane.halfCyl_eventually_ne_zero

by Mazecto · Oct 21, 2026 · Mathlib 0df444a (Lean v4.33.1)

asymptotic-operatorpseudoholomorphic-curvesreeb-dynamicssymplectic-geometrysymplectization

Let S:R2→R2n×2nS:\mathbb{R}^2\to\mathbb{R}^{2n\times2n}S:R2→R2n×2n be C∞C^\inftyC∞ and 111-periodic in ttt, and S∞S_\inftyS∞​ a C∞C^\inftyC∞ 111-periodic loop of symmetric matrices with S→S∞S\to S_\inftyS→S∞​ in C∞C^\inftyC∞. Let ζ\zetaζ be a solution of ∂sζ+J0∂tζ+Sζ=0\partial_s\zeta+J_0\partial_t\zeta+S\zeta=0∂s​ζ+J0​∂t​ζ+Sζ=0 on the half-cylinder, not identically zero on (0,∞)×R(0,\infty)\times\mathbb{R}(0,∞)×R, with ∥ζ(s,t)∥≤Ceδ0s\|\zeta(s,t)\|\le Ce^{\delta_0s}∥ζ(s,t)∥≤Ceδ0​s for s>0s>0s>0. Then there is s0s_0s0​ with ζ(s,t)≠0\zeta(s,t)\neq0ζ(s,t)=0 for all s≥s0s\ge s_0s≥s0​ and all ttt.

Formalization Note No rate of convergence of SSS and no nondegeneracy of S∞S_\inftyS∞​ is assumed.

Preamble
import Definitions.Def_FiniteEnergyPlane_Asymptotics
Formal statement
namespace FiniteEnergyPlane

open MeasureTheory Metric Filter Topology
open scoped ContDiff ENNReal Real

/-- A solution of `∂ₛζ + J₀ ∂ₜζ + S ζ = 0` on a half-cylinder, with `S(s, t) → S∞(t)` in `C^∞`,
not identically zero and with `‖ζ(s, t)‖ ≤ C e^{δ₀ s}`, has no zeros for `s` large. -/
theorem halfCyl_eventually_ne_zero {n : ℕ} (S : ℝ × ℝ → CauchyRiemannIndex.Mat n)
    (hS : ∀ i j, ContDiff ℝ ∞ (fun p : ℝ × ℝ => S p i j)) (hSper : ∀ s t : ℝ, S (s, t + 1) = S (s, t))
    (Sinf : ℝ → CauchyRiemannIndex.Mat n) (hSinf : CauchyRiemannIndex.IsSymLoop Sinf)
    (hSinf' : ∀ i j, ContDiff ℝ ∞ (fun t => Sinf t i j))
    (hSas : IsCInftyAsymptoticTo S Sinf)
    (ζ : ℝ × ℝ → CauchyRiemannIndex.Vec n) (hζ : IsHalfCylSolution S ζ)
    (hne : ∃ p : ℝ × ℝ, 0 < p.1 ∧ ζ p ≠ 0)
    (C δ₀ : ℝ) (hgrowth : ∀ s > 0, ∀ t : ℝ, ‖ζ (s, t)‖ ≤ C * Real.exp (δ₀ * s)) :
    ∃ s₀ : ℝ, ∀ s ≥ s₀, ∀ t : ℝ, ζ (s, t) ≠ 0 := by
  sorry

end FiniteEnergyPlane
Source
C. Wendl, Lectures on Symplectic Field Theory, lecture notes, Humboldt-Universität zu Berlin (2026 version); earlier version arXiv:1612.01009, Corollary 4.8.3
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What the Lean code literally says, in plain math · claude-opus-5-5

Read-back: FiniteEnergyPlane.halfCyl_eventually_ne_zero

Notation. n≥0n \ge 0n≥0 is an arbitrary natural number (including n=0n = 0n=0). Matn\mathrm{Mat}_nMatn​ is the space of real 2n×2n2n \times 2n2n×2n matrices, rows and columns indexed by two copies of {0,…,n−1}\{0, \dots, n-1\}{0,…,n−1}; Vecn=R2n\mathrm{Vec}_n = \mathbb{R}^{2n}Vecn​=R2n with the Euclidean norm, indexed the same way. J0∈MatnJ_0 \in \mathrm{Mat}_nJ0​∈Matn​ is the block matrix (0−II0)\begin{pmatrix} 0 & -I \\ I & 0 \end{pmatrix}(0I​−I0​). Matrices act on Vecn\mathrm{Vec}_nVecn​ by matrix–vector multiplication. For ζ:R2→Vecn\zeta : \mathbb{R}^2 \to \mathrm{Vec}_nζ:R2→Vecn​, ∂sζ(s,t)=Dζ(s,t)(1,0)\partial_s \zeta(s,t) = D\zeta(s,t)(1,0)∂s​ζ(s,t)=Dζ(s,t)(1,0) and ∂tζ(s,t)=Dζ(s,t)(0,1)\partial_t \zeta(s,t) = D\zeta(s,t)(0,1)∂t​ζ(s,t)=Dζ(s,t)(0,1) (Fréchet derivative; 000 where not differentiable). For matrix-valued or scalar f:R2→Ff : \mathbb{R}^2 \to Ff:R2→F, DmfD^m fDmf is the mmm-th Fréchet derivative (operator norm, R2\mathbb{R}^2R2 with the max norm), and "f→0f \to 0f→0 in C∞C^\inftyC∞" means: fff is C∞C^\inftyC∞ on (s0,∞)×R(s_0, \infty) \times \mathbb{R}(s0​,∞)×R for some s0s_0s0​, and for every m∈Nm \in \mathbb{N}m∈N and ϵ>0\epsilon > 0ϵ>0 there is s1s_1s1​ with ∥Dmf(s,t)∥≤ϵ\|D^m f(s,t)\| \le \epsilon∥Dmf(s,t)∥≤ϵ for all s≥s1s \ge s_1s≥s1​, t∈Rt \in \mathbb{R}t∈R.

Data and hypotheses.

  • S:R2→MatnS : \mathbb{R}^2 \to \mathrm{Mat}_nS:R2→Matn​ such that every entry (s,t)↦S(s,t)ij(s,t) \mapsto S(s,t)_{ij}(s,t)↦S(s,t)ij​ is C∞C^\inftyC∞ on R2\mathbb{R}^2R2, and S(s,t+1)=S(s,t)S(s, t+1) = S(s, t)S(s,t+1)=S(s,t) for all s,ts, ts,t.
  • S∞:R→MatnS_\infty : \mathbb{R} \to \mathrm{Mat}_nS∞​:R→Matn​ which is continuous, 111-periodic, with S∞(t)S_\infty(t)S∞​(t) symmetric for every ttt, and with every entry t↦S∞(t)ijt \mapsto S_\infty(t)_{ij}t↦S∞​(t)ij​ C∞C^\inftyC∞.
  • For every i,ji, ji,j: S(s,t)ij−S∞(t)ij→0S(s,t)_{ij} - S_\infty(t)_{ij} \to 0S(s,t)ij​−S∞​(t)ij​→0 in C∞C^\inftyC∞ (as a function of (s,t)(s,t)(s,t), as s→+∞s \to +\inftys→+∞).
  • ζ:R2→Vecn\zeta : \mathbb{R}^2 \to \mathrm{Vec}_nζ:R2→Vecn​ is C∞C^\inftyC∞ on (0,∞)×R(0, \infty) \times \mathbb{R}(0,∞)×R, satisfies ζ(s,t+1)=ζ(s,t)\zeta(s, t+1) = \zeta(s, t)ζ(s,t+1)=ζ(s,t) for all real s,ts, ts,t, and
∂sζ(s,t)+J0 ∂tζ(s,t)+S(s,t) ζ(s,t)=0for all s>0, t∈R.\partial_s \zeta(s,t) + J_0\, \partial_t \zeta(s,t) + S(s,t)\, \zeta(s,t) = 0 \qquad \text{for all } s > 0,\ t \in \mathbb{R}.∂s​ζ(s,t)+J0​∂t​ζ(s,t)+S(s,t)ζ(s,t)=0for all s>0, t∈R.
  • There is a point (s,t)(s,t)(s,t) with s>0s > 0s>0 and ζ(s,t)≠0\zeta(s,t) \ne 0ζ(s,t)=0.
  • Real numbers CCC and δ0\delta_0δ0​ (no sign or size restriction) with ∥ζ(s,t)∥≤C eδ0s\|\zeta(s,t)\| \le C\, e^{\delta_0 s}∥ζ(s,t)∥≤Ceδ0​s for all s>0s > 0s>0, t∈Rt \in \mathbb{R}t∈R. (Since the left side is ≥0\ge 0≥0, this hypothesis can only hold with C≥0C \ge 0C≥0.)

Conclusion. There exists s0∈Rs_0 \in \mathbb{R}s0​∈R such that ζ(s,t)≠0\zeta(s,t) \ne 0ζ(s,t)=0 for every s≥s0s \ge s_0s≥s0​ and every t∈Rt \in \mathbb{R}t∈R.

Remarks on edge cases. No nondegeneracy or invertibility assumption on S∞S_\inftyS∞​ (or on the operator −J0ddt−S∞-J_0 \frac{d}{dt} - S_\infty−J0​dtd​−S∞​) is made. For n=0n = 0n=0, Vec0={0}\mathrm{Vec}_0 = \{0\}Vec0​={0}, so the hypothesis that ζ\zetaζ is somewhere nonzero cannot hold and the statement is vacuous. The value of s0s_0s0​ is not constrained (it need not be positive).

Human review
  • Endorsed by Shuze Chen · Oct 21, 2026

    Confirmed by the moderator at approval.

  • Endorsed by Mazecto · Oct 21, 2026

    Confirmed by the mission captain (proposal self-audit).

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