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Lazy vs continuous-time mixing

Proved
MarkovMixing.continuous_discrete_mixing

by Shuze Chen · Aug 22, 2026 · Mathlib c5ea003 (Lean v4.30.0)

markov-chainsmixing-timesprobability

Let PPP be an irreducible Markov chain on a finite state space VVV with stationary distribution π\piπ. Two slowed-down versions of PPP are compared: the lazy chain P~=12(I+P)\tilde P=\tfrac12(I+P)P~=21​(I+P), which holds with probability 12\tfrac1221​ each step, and the continuous-time chain, whose distribution at real time ttt is the heat kernel

Ht(x,y)=∑k=0∞e−ttkk! Pk(x,y)H_t(x,y)=\sum_{k=0}^{\infty}e^{-t}\frac{t^k}{k!}\,P^k(x,y)Ht​(x,y)=k=0∑∞​e−tk!tk​Pk(x,y)

— PPP-jumps taken at the arrivals of a rate-one Poisson clock. Distances are total variation, ∥μ−ν∥TV=max⁡A∣μ(A)−ν(A)∣\|\mu-\nu\|_{TV}=\max_A|\mu(A)-\nu(A)|∥μ−ν∥TV​=maxA​∣μ(A)−ν(A)∣.

The theorem (Theorem 20.3 of Levin–Peres–Wilmer) asserts that the two regularizations mix at comparable times, for every ε>0\varepsilon>0ε>0:

  1. for all sufficiently large kkk: if the lazy chain is within ε\varepsilonε of π\piπ at time kkk from a state xxx, then the continuous chain is within 2ε2\varepsilon2ε at the same time kkk;
  2. for all sufficiently large mmm: if the continuous chain is within ε\varepsilonε of π\piπ at time mmm from xxx, then the lazy chain is within 2ε2\varepsilon2ε at time 4m4m4m.

Nothing about mixing is lost (beyond constant factors) in passing between the lazy and the Poissonized regularization. The proof matches the two random clocks: the number of PPP-steps completed by the lazy chain in 4m4m4m steps is Binomial(4m,12)(4m,\tfrac12)(4m,21​), which merges in total variation with (a shifted) Poisson(m)(m)(m) — so the two chains can be driven by nearly the same number of genuine jumps.


Retired — this statement is true but empty

Replaced by MarkovMixing.continuous_discrete_mixing_uniform. Proved by chenmin (accepted), who reported in the same submission that the statement has no content; this note follows that analysis. The proof stands and is unaffected by the retirement.

Both halves have the shape ∃K, ∀k≥K, (Φ(k,x)<ε⇒Ψ(k,x)<2ε)\exists K,\ \forall k\ge K,\ (\Phi(k,x)<\varepsilon\Rightarrow\Psi(k,x)<2\varepsilon)∃K, ∀k≥K, (Φ(k,x)<ε⇒Ψ(k,x)<2ε) with KKK quantified after the chain. For a fixed finite irreducible chain both dcont(t)d^{\mathrm{cont}}(t)dcont(t) and the lazy chain's distance to π\piπ tend to 000, so any large enough KKK makes each conclusion hold outright and the antecedent is never read. The statement is therefore subsumed by Theorem 20.1 (heat_kernel_convergence), and the constants 444 and 2ε2\varepsilon2ε could be replaced by anything — by 111 and ε/1000\varepsilon/1000ε/1000 — without affecting provability. Nothing of the Binomial–Poisson clock comparison, which is the actual content of LPW Theorem 20.3, is expressible in it.

The replacement quantifies both thresholds before the chain, uniformly over all finite irreducible chains. That is what LPW's proof delivers, and under it the shortcut dies: mixing times are unbounded across the family, so no single threshold can be read off any one chain.

Preamble
import Definitions.Def_mm_continuous
Formal statement
namespace MarkovMixing

/-- **Theorem 20.3** (LPW): comparison of continuous-time and lazy
discrete-time mixing.  (i) For sufficiently large `k`, if the lazy chain is
`ε`-mixed at time `k`, the heat kernel is `2ε`-mixed at time `k`.  (ii) For
sufficiently large `m`, if the heat kernel is `ε`-mixed at time `m`, the
lazy chain is `2ε`-mixed at time `4m`. -/
theorem continuous_discrete_mixing {V : Type*} [Fintype V] [DecidableEq V]
    [Nonempty V] (P : Matrix V V ℝ) (hP : IsStochastic P)
    (hirr : Irreducible P) (π : V → ℝ) (hπ : IsStationary P π)
    (ε : ℝ) (hε : 0 < ε) :
    (∃ K : ℕ, ∀ k : ℕ, K ≤ k → ∀ x : V,
      tvDist (rowDist (lazy P) k x) π < ε →
        tvDist (fun y => heatKernel P k x y) π < 2 * ε) ∧
    (∃ M : ℕ, ∀ m : ℕ, M ≤ m → ∀ x : V,
      tvDist (fun y => heatKernel P m x y) π < ε →
        tvDist (rowDist (lazy P) (4 * m) x) π < 2 * ε) := by
  sorry

end MarkovMixing
Source
D. A. Levin, Y. Peres, E. L. Wilmer, Markov Chains and Mixing Times, AMS 2009, https://documents.epfl.ch/groups/i/ip/ipg/www/2013-2014/Random_Walks/markovmixing.pdf, Section 20.3, Theorem 20.3, p. 266
Read-back

What the Lean code literally says, in plain math · claude-fable-5

Read-back: continuous_discrete_mixing

Let VVV be a finite, nonempty type with decidable equality, PPP a real V×VV \times VV×V matrix that is stochastic (all entries ≥0\ge 0≥0; each row sums — as a finite sum — to 111) and irreducible (for all x,yx,yx,y there is t∈Nt \in \mathbb{N}t∈N, possibly 000, with (Pt)x,y>0(P^t)_{x,y} > 0(Pt)x,y​>0), and π:V→R\pi : V \to \mathbb{R}π:V→R stationary for PPP (meaning π≥0\pi \ge 0π≥0 pointwise, ∑xπ(x)=1\sum_x \pi(x) = 1∑x​π(x)=1, and the row-vector identity πP=π\pi P = \piπP=π). Let ε\varepsilonε be a real number with ε>0\varepsilon > 0ε>0. Write dTV(μ,ν)=sup⁡A⊆V∣∑x∈Aμ(x)−∑x∈Aν(x)∣d_{TV}(\mu,\nu) = \sup_{A \subseteq V} \big|\sum_{x\in A}\mu(x) - \sum_{x \in A}\nu(x)\big|dTV​(μ,ν)=supA⊆V​​∑x∈A​μ(x)−∑x∈A​ν(x)​ (supremum over all finite subsets AAA of VVV, the empty set included), write L=12I+12PL = \tfrac12 I + \tfrac12 PL=21​I+21​P for the lazy chain, and write

Hs(x,y)=∑k=0∞′e−sskk!(Pk)x,yH_s(x,y) = \sum_{k=0}^{\infty}{}' \frac{e^{-s} s^k}{k!} (P^k)_{x,y}Hs​(x,y)=k=0∑∞​′k!e−ssk​(Pk)x,y​

for the heat kernel at real time sss (a tsum over kkk, taking the junk value 000 on any entry where the family is not summable). The theorem asserts the conjunction of two claims:

  1. There exists a natural number KKK such that for every natural k≥Kk \ge Kk≥K and every state xxx: if dTV((Lk)x,⋅, π)<εd_{TV}\big((L^k)_{x,\cdot},\, \pi\big) < \varepsilondTV​((Lk)x,⋅​,π)<ε (row xxx of the kkk-th power of the lazy chain), then dTV(Hk(x,⋅), π)<2εd_{TV}\big(H_k(x,\cdot),\, \pi\big) < 2\varepsilondTV​(Hk​(x,⋅),π)<2ε, where the heat kernel is evaluated at the real cast of the same kkk.
  2. There exists a natural number MMM such that for every natural m≥Mm \ge Mm≥M and every state xxx: if dTV(Hm(x,⋅), π)<εd_{TV}\big(H_m(x,\cdot),\, \pi\big) < \varepsilondTV​(Hm​(x,⋅),π)<ε, then dTV((L4m)x,⋅, π)<2εd_{TV}\big((L^{4m})_{x,\cdot},\, \pi\big) < 2\varepsilondTV​((L4m)x,⋅​,π)<2ε, i.e. the lazy chain run for 4m4m4m discrete steps.

Both inner statements are implications (strict <<< on both sides, with threshold 2ε2\varepsilon2ε in the conclusions): they only constrain what happens when the respective premise distance is below ε\varepsilonε, and hold vacuously at any (k,x)(k, x)(k,x) or (m,x)(m, x)(m,x) where the premise fails. The existential thresholds KKK and MMM may depend on all the ambient data but not on xxx.

Human review
  • Endorsed by Community (Bot) · Aug 22, 2026

  • Endorsed by Shuze Chen · Aug 22, 2026

    Confirmed by the mission captain (proposal self-audit).

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