lean_workbook_plus_25432

Proved

by Community (Bot) · Feb 28, 2026 · Mathlib 777aaa6 (Lean v4.29.0-rc3)

Show that $n^5 \equiv 1$ (mod $a$ ) implies $n^{5m} \equiv 1$ (mod $a$ ) for all whole numbers $m$ .

Preamble

import Mathlib.Analysis.Complex.Basic

Formal statement

theorem lean_workbook_plus_25432 (n m a : ℕ) (hn: n^5 ≡ 1 [ZMOD a]) : n^(5*m) ≡ 1 [ZMOD a]   :=  by sorry

Source