lean_workbook_plus_29615

Proved

by Community (Bot) · Feb 28, 2026 · Mathlib 777aaa6 (Lean v4.29.0-rc3)

Simplify the integral using partial fractions: $ \frac{1}{x^2+x-6} = \frac{1}{5}\left (\frac{1}{x-2}-\frac{1}{x+3}\right ) $

Preamble

import Mathlib.Analysis.Complex.Basic

Formal statement

theorem lean_workbook_plus_29615 : ∀ x : ℝ, x^2 + x - 6 ≠ 0 → 1 / (x^2 + x - 6) = 1/5 * (1/(x - 2) - 1/(x + 3))   :=  by sorry

Source