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Matrix integral inequality for rational regularized Gram matrices

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RybinAI2026.P01.matrix_integral_inequality_rational_gram

by ryanshin · Sep 5, 2026 · Mathlib c5ea003 (Lean v4.30.0)

integral-inequalitymatrix-analysispositive-definite-matrices

Let n>0n>0n>0 and k≥0k\geq 0k≥0 be integers, and let P,Q,R,SP,Q,R,SP,Q,R,S be rational n×nn\times nn×n matrices. Regard their entries as real numbers, put εk=1/(k+1)\varepsilon_k=1/(k+1)εk​=1/(k+1), and define

A=PTP+εkIn,B=QTQ+εkIn,C=RTR+εkIn,D=STS+εkIn.A=P^{\mathsf T}P+\varepsilon_k I_n,\qquad B=Q^{\mathsf T}Q+\varepsilon_k I_n,\qquad C=R^{\mathsf T}R+\varepsilon_k I_n,\qquad D=S^{\mathsf T}S+\varepsilon_k I_n.A=PTP+εk​In​,B=QTQ+εk​In​,C=RTR+εk​In​,D=STS+εk​In​.

For real positive-definite matrices X,YX,YX,Y, write

d(X,Y)=∫Sn−1∫Sn−1∣uT(X−Y)v∣(uTXu)(vTYv) dσ(v) dσ(u),d(X,Y)=\int_{S^{n-1}}\int_{S^{n-1}} \frac{|u^{\mathsf T}(X-Y)v|} {(u^{\mathsf T}Xu)(v^{\mathsf T}Yv)}\,d\sigma(v)\,d\sigma(u),d(X,Y)=∫Sn−1​∫Sn−1​(uTXu)(vTYv)∣uT(X−Y)v∣​dσ(v)dσ(u),

where σ\sigmaσ is the unnormalized surface measure obtained from Euclidean Lebesgue volume by polar decomposition. The assertion is

d(A+B,C+D)≤max⁡{d(A,C),d(B,D)}.d(A+B,C+D)\leq\max\{d(A,C),d(B,D)\}.d(A+B,C+D)≤max{d(A,C),d(B,D)}.

Every matrix displayed above is positive definite, regardless of whether the rational matrices are singular. This is the restriction of Problem 1 to a countable family with rational entries and a common positive regularization parameter. It is the unresolved arithmetic case used by the approximation reduction of the general real-matrix problem; it is not asserted to have been proved.

Preamble
import Definitions.Def_rybin2026_p01_matrix_integral

open Matrix RybinAI2026.P01
Formal statement
theorem RybinAI2026.P01.matrix_integral_inequality_rational_gram
    {n : ℕ} (hn : 0 < n) (k : ℕ)
    (P Q R S : Matrix (Fin n) (Fin n) ℚ) :
    let p : Matrix (Fin n) (Fin n) ℝ := P.map (fun q : ℚ => (q : ℝ))
    let q : Matrix (Fin n) (Fin n) ℝ := Q.map (fun q : ℚ => (q : ℝ))
    let r : Matrix (Fin n) (Fin n) ℝ := R.map (fun q : ℚ => (q : ℝ))
    let s : Matrix (Fin n) (Fin n) ℝ := S.map (fun q : ℚ => (q : ℝ))
    let A := p.transpose * p + ((k : ℝ) + 1)⁻¹ • 1
    let B := q.transpose * q + ((k : ℝ) + 1)⁻¹ • 1
    let C := r.transpose * r + ((k : ℝ) + 1)⁻¹ • 1
    let D := s.transpose * s + ((k : ℝ) + 1)⁻¹ • 1
    distance (A + B) (C + D) ≤ max (distance A C) (distance B D) := by
  sorry
Source
https://rybindmitry.github.io/problems/1.html, Problem 1, restricted to rational Gram matrices with the common regularizer I/(k+1). The general statement is recovered by the separately formalized continuity and density reduction.

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