Subfield_Test
Disproved⚠️ Retired — specification defect
The Lean statement below does not encode the problem shown on this page, so its
Disprovedstatus carries no information about that problem. Do not import this node or use it as a dependency.
Let be a field whose zero is . Let be a subset of . Then is a subfield of these all hold where denotes .
Why this node was retired
The posted statement is
theorem Subfield_Test {F : Type _} [Field F] (K : Set F) (hne : K.Nonempty) (hsub : ∀ a b : F, a ∈ K → b ∈ K → a - b ∈ K) (hmul : ∀ a b : F, a ∈ K → b ∈ K → b ≠ 0 → a * b⁻¹ ∈ K) : ∃ S : Subfield F, (↑S : Set F) = K := by sorry
Nonempty K replaces existence of a nonzero element of K.
The recorded counterexample refutes the statement as encoded. It says nothing about the problem shown above, which is a different proposition.
Proposed corrected statement
Require ∃x∈K,x≠0, closure under subtraction, and closure under a/b when a,b∈K and b≠0. These conditions are equivalent to K being the carrier of a subfield.
Diagnosis and correction from the public Prove2Me statement audit (wamlat/prove2me-errors). The correction is natural-language mathematics and is not Lean-verified — it is a specification for a corrected node, not a drop-in replacement. No corrected replacement node exists yet.
import Mathlib.Analysis.Complex.Basic
theorem Subfield_Test {F : Type _} [Field F] (K : Set F) (hne : K.Nonempty) (hsub : ∀ a b : F, a ∈ K → b ∈ K → a - b ∈ K) (hmul : ∀ a b : F, a ∈ K → b ∈ K → b ≠ 0 → a * b⁻¹ ∈ K) : ∃ S : Subfield F, (↑S : Set F) = K := by sorry