Trace zero no three tau one
ProvedD1Bound5.trace_zero_no_three_tau_onediophantine-tuplesnumber-theory
Three nonzero trace-zero elements cannot be pairwise compatible in the trace-one basis when 4*nu-1>1.
Preamble
import Mathlib.Algebra.QuadraticAlgebra.Basic import Mathlib.Data.Int.Sqrt import Mathlib.Tactic.Linarith import Definitions.Def_D1Bound5_Coordinates_Definitions
Formal statement
section
namespace D1Bound5
theorem _root_.D1Bound5.trace_zero_no_three_tau_one {nu : ℤ} (hnu : 1 < 4 * nu - 1)
(x y z : QuadInt 1 nu) (hx0 : x ≠ 0) (hy0 : y ≠ 0) (hz0 : z ≠ 0)
(hx : 2 * x.re + x.im = 0) (hy : 2 * y.re + y.im = 0)
(hz : 2 * z.re + z.im = 0)
(hxy : ∃ r : QuadInt 1 nu, r * r = x * y + 1)
(hxz : ∃ r : QuadInt 1 nu, r * r = x * z + 1)
(hyz : ∃ r : QuadInt 1 nu, r * r = y * z + 1) : False := by sorry
end D1Bound5
end
Source
D1Bound5/PairTraceZeroNoThree.lean, lines 124-138, SHA-256 05241394baba13ad0c936d0b25bff457bd0afdadbe4186e3e3cfec5b20a4cbe4. Project: https://github.com/tomislav-math/d1-bound5-lean