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New Minimal Standard Model: one neutrino is exactly massless

Proved
NewMinimalStandardModel.exists_massless_neutrino

by Lucas · Oct 4, 2026 · Mathlib 0df444a (Lean v4.33.1)

linear-algebramathematical-physicsneutrino-physics

Let v∈Rv\in\mathbb Rv∈R (with ⟨H⟩=v/2\langle H\rangle = v/\sqrt2⟨H⟩=v/2​), let hνh_\nuhν​ be a complex 2×32\times 32×3 Yukawa matrix, and let M1,M2>0M_1,M_2>0M1​,M2​>0 be the masses of the two right-handed neutrinos of Eq. (4). Let

M=(0mDTmDdiag⁡(M1,M2)),mD=v2hν,\mathcal M = \begin{pmatrix} 0 & m_D^{\mathsf T} \\ m_D & \operatorname{diag}(M_1,M_2)\end{pmatrix},\qquad m_D=\frac{v}{\sqrt2}h_\nu,M=(0mD​​mDT​diag(M1​,M2​)​),mD​=2​v​hν​,

be the 5×55\times55×5 Majorana mass matrix of (ν1,ν2,ν3,N1,N2)(\nu_1,\nu_2,\nu_3,N_1,N_2)(ν1​,ν2​,ν3​,N1​,N2​). Then one of its physical masses vanishes exactly:

∃ i:σi(M)=λi(M†M)=0.\exists\, i:\quad \sigma_i(\mathcal M) = \sqrt{\lambda_i(\mathcal M^\dagger\mathcal M)} = 0 .∃i:σi​(M)=λi​(M†M)​=0.

This is the NMSM prediction that, with only two right-handed neutrinos, "one of the neutrino masses exactly vanishes (ignoring tiny Planck suppressed effects)" (p. 122), so that a neutrinoless double-beta-decay signal in near-future experiments is possible only for the inverted hierarchy.

Formalization Note The statement concerns the full tree-level neutral-lepton mass matrix, not the seesaw approximation; positivity of M1,M2M_1,M_2M1​,M2​ is the source's convention for the diagonal real basis.

Preamble
import Mathlib
import Definitions.Def_NewMinimalStandardModel_Defs
Formal statement
namespace NewMinimalStandardModel

theorem exists_massless_neutrino (v : ℝ) (hν : Matrix (Fin 2) (Fin 3) ℂ) (M : Fin 2 → ℝ)
    (hM : ∀ α, 0 < M α) :
    ∃ i, majoranaMasses (neutralLeptonMassMatrix v hν M) i = 0 := by sorry

end NewMinimalStandardModel
Source
H. Davoudiasl, R. Kitano, T. Li, H. Murayama, The new Minimal Standard Model, Phys. Lett. B 609 (2005) 117-123, https://doi.org/10.1016/j.physletb.2005.01.026, p. 119 (Eq. (4) and the following discussion) and p. 122 ("one of the neutrino masses exactly vanishes")
Read-back

What the Lean code literally says, in plain math · Aristotle (Harmonic) - same agent that drafted the statements; NON-BLIND, not an independent auditor

NON-BLIND READ-BACK — NOT INDEPENDENT TESTIMONY. This read-back was written by the same agent that drafted the Lean statement, with full knowledge of the source paper and of the intended meaning. It was not produced by a blind, independent auditor and must not be treated as independent evidence of faithfulness. Reviewers should compare the Lean code against the source themselves.

For every real vvv, every complex 2×32\times32×3 matrix hνh_\nuhν​, and all reals M1>0M_1>0M1​>0, M2>0M_2>0M2​>0, let M\mathcal MM be the complex matrix indexed by {1,2,3}⊔{1,2}\{1,2,3\}\sqcup\{1,2\}{1,2,3}⊔{1,2} with block form

M=(03×3(v2hν)Tv2hνdiag⁡(M1,M2))\mathcal M=\begin{pmatrix} 0_{3\times3} & \big(\tfrac{v}{\sqrt2}h_\nu\big)^{\mathsf T}\\ \tfrac{v}{\sqrt2}h_\nu & \operatorname{diag}(M_1,M_2)\end{pmatrix}M=(03×3​2​v​hν​​(2​v​hν​)Tdiag(M1​,M2​)​)

(plain transpose). The theorem asserts that there exists an index iii (among the five) such that λi=0\sqrt{\lambda_i}=0λi​​=0, where (λi)(\lambda_i)(λi​) are the eigenvalues of the Hermitian matrix M†M\mathcal M^\dagger\mathcal MM†M as enumerated by Mathlib's spectral theorem. It does not assert how many such indices exist, and places no condition on vvv or hνh_\nuhν​.

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