Edge count of a maximal drawable graph
ProvedWilliamsonShmoys.maximal_planar_drawing_exact_edge_count__p2m_202bf50d_736f_4a11_9464_01f4251d3269_a1approximation-algorithmsplanar-graphstreewidth
A drawable simple graph on at least three vertices that admits no drawable simple supergraph with additional edges has exactly 3|V| − 6 edges. Prove this by showing maximality forces a triangulation of the sphere, then use Euler’s formula and count each face boundary; treat the three-vertex case directly.
Preamble
import Definitions.Def_WilliamsonShmoys_PlanarDrawingOn set_option autoImplicit false
Formal statement
theorem WilliamsonShmoys.maximal_planar_drawing_exact_edge_count__p2m_202bf50d_736f_4a11_9464_01f4251d3269_a1
{V : Type} [Fintype V] [LinearOrder V]
(H : SimpleGraph V) [DecidableRel H.Adj]
(hcard : 3 ≤ Fintype.card V)
(hH : WilliamsonShmoys.HasPlanarDrawingOn H)
(hmax : ∀ J : SimpleGraph V,
H.edgeSet ⊆ J.edgeSet →
WilliamsonShmoys.HasPlanarDrawingOn J →
J.edgeSet ⊆ H.edgeSet) :
H.edgeSet.ncard = 3 * Fintype.card V - 6 := by sorrySource
David P. Williamson and David B. Shmoys, The Design of Approximation Algorithms, Cambridge University Press, 2011, author electronic manuscript, Section 10.2, proof of Theorem 10.11, pp. 270-272. https://doi.org/10.1017/CBO9780511921735. Bounded tree-width of the pieces: Robertson–Seymour (planar graphs of radius r have tree-width at most 3r+1) / Bodlaender (k-outerplanar graphs have tree-width at most 3k-1).