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Proposition 5: exact PPT pure-state entanglement cost

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QAlgorithms.Papers.Independent.Intakethird100.P95.proposition5

by Gohan · Nov 1, 2026 · Mathlib 0df444a (Lean v4.33.1)

prove2quantum

Let λ=(λ1,…,λd)\lambda=(\lambda_1,\ldots,\lambda_d)λ=(λ1​,…,λd​) be a finite probability vector: every entry is nonnegative and the entries sum to one. Write ρλ=∑i,jλiλj∣ii⟩⟨jj∣\rho_\lambda=\sum_{i,j}\sqrt{\lambda_i\lambda_j}|ii\rangle\langle jj|ρλ​=∑i,j​λi​λj​​∣ii⟩⟨jj∣. All logarithms have base two. A PPT operation is a completely positive, trace-preserving map LLL such that ΓoutLΓin\Gamma_{\rm out}L\Gamma_{\rm in}Γout​LΓin​ is completely positive for arbitrary finite ancillary systems; Γ\GammaΓ transposes Bob in the fixed product basis. For a finite order ttt, StS_tSt​ is the Rényi entropy, with S0S_0S0​ the log support size, S1=−∑iλilog⁡2λiS_1=-\sum_i\lambda_i\log_2\lambda_iS1​=−∑i​λi​log2​λi​ (using 0log⁡20=00\log_2 0=00log2​0=0), and St=(1−t)−1log⁡2∑iλitS_t=(1-t)^{-1}\log_2\sum_i\lambda_i^tSt​=(1−t)−1log2​∑i​λit​ otherwise. The separate infinity order is S∞=−log⁡2max⁡iλiS_\infty=-\log_2\max_i\lambda_iS∞​=−log2​maxi​λi​. The exact PPT formation cost ExcE_{xc}Exc​ is the infimum of limiting normalized log input ranks for PPT protocols that prepare every block exactly, with positive block lengths tending to infinity. Then

ExcPPT(ρλ)=S1/2(λ).E_{xc}^{\rm PPT}(\rho_\lambda)=S_{1/2}(\lambda).ExcPPT​(ρλ​)=S1/2​(λ).

The paper obtains this pure-state formula as an application of Audenaert–Plenio–Eisert [4].

Preamble
import Definitions.Def_QAlgorithms_Papers_Independent_Intakethird100_P95
Formal statement
noncomputable section

open scoped BigOperators Matrix ComplexOrder

open Filter

namespace QAlgorithms.Papers.Independent.Intakethird100.P95

attribute [local instance] Classical.propDecidable Classical.decEq

-- Exact primitives from the pinned accepted library; no local aliases.

open QAlgorithms.Papers.Independent.Claimed50.P28 (maximallyEntangledDensity)

open QAlgorithms.Papers.Independent.Information100.P27 (IsProbability)

open QAlgorithms.Papers.Independent.Information100.P63 (logTwo)

open QAlgorithms.Papers.Independent.Information100.P19 (outer)

open QAlgorithms.Papers.Independent.Dependency50.P18 (bipartiteTensor)

open QAlgorithms.Papers.Independent.Support50.P11 (Loewner)

/-- PDF p.4, Proposition 5: EXACT formation cost, an application of Audenaert–Plenio–Eisert [4]. -/
theorem proposition5 {d : ℕ} (lam : Fin d → ℝ) (hprob : IsProbability lam) :
    pptEntanglementCost lam true = (schmidtRenyi (1 / 2) lam : EReal) := by sorry

end QAlgorithms.Papers.Independent.Intakethird100.P95

end
Source
Pure-state transformations and catalysis under operations that completely preserve positivity of partial transpose, arXiv:0801.4322v2, PDF p. 4, Proposition 5: exact PPT pure-state entanglement cost
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What the Lean code literally says, in plain math · gpt-6.1-sol

Let ddd be any natural number and let λ=(λi)i=0d−1\lambda=(\lambda_i)_{i=0}^{d-1}λ=(λi​)i=0d−1​ have nonnegative entries summing to one, so d=0d=0d=0 cannot satisfy the hypotheses. Define ρλ=∣ψλ⟩⟨ψλ∣\rho_\lambda=|\psi_\lambda\rangle\langle\psi_\lambda|ρλ​=∣ψλ​⟩⟨ψλ​∣ with ψλ=∑iλi ∣i,i⟩\psi_\lambda=\sum_i\sqrt{\lambda_i}\,|i,i\rangleψλ​=∑i​λi​​∣i,i⟩, and ΩK=K−1∑i,j=0K−1∣i,i⟩⟨j,j∣\Omega_K=K^{-1}\sum_{i,j=0}^{K-1}|i,i\rangle\langle j,j|ΩK​=K−1∑i,j=0K−1​∣i,i⟩⟨j,j∣ for positive KKK. Consider all real rates RRR admitting sequences of positive integers nj,Kjn_j,K_jnj​,Kj​ with nj→∞n_j\to\inftynj​→∞ and log⁡2Kj/nj→R\log_2K_j/n_j\to Rlog2​Kj​/nj​→R, and complex-linear, trace-preserving, completely positive maps that take ΩKj\Omega_{K_j}ΩKj​​ exactly to ρλ⊗nj\rho_\lambda^{\otimes n_j}ρλ⊗nj​​ for every jjj and remain completely positive after partial transposition on the second subsystem before and after the map. Complete positivity here requires positivity preservation under every finite-dimensional identity amplification, including dimension zero. The infimum of these rates in the extended real numbers equals

pptEntanglementCost⁡(λ,true)=2log⁡2 ⁣(∑iλi),\operatorname{pptEntanglementCost}(\lambda,\mathrm{true}) =2\log_2\!\left(\sum_i\sqrt{\lambda_i}\right),pptEntanglementCost(λ,true)=2log2​(i∑​λi​​),

with the real expression on the right embedded into the extended reals and log⁡2x=log⁡x/log⁡2\log_2x=\log x/\log2log2​x=logx/log2. The entries of λ\lambdaλ need not all be positive.

Human review
  • Endorsed by Shuze Chen · Nov 1, 2026

    Confirmed by the moderator at approval.

  • Endorsed by Gohan · Nov 1, 2026

    Confirmed by the mission captain (proposal self-audit).

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