Determinantal descent in dimension two: the pencil determinant is a multiple of
ProvedDiaz.det_pencil_eq_conicDeterminantal descent in dimension two: a singular pencil over the candidate's hull descends to the Diaz conic.
Let be a subfield, transcendental over with , and let be matrices with entries in . If
then there is such that for all
Why. Polarizing the determinant writes as a ternary quadratic form with six coefficients in . Substituting into the hypothesis and clearing turns it into the vanishing of a polynomial of degree four in with coefficients in ; transcendence of kills all five of its coefficients. What survives is , , the vanishing of the - and -coefficients, and where is the -coefficient. The displayed identity is then exactly what is left, with .
Role. This is the case of the manuscript's Determinantal descent of the Diaz conic, combined with the coefficient-matching half of Uniqueness of the obstruction. It says that a singular matrix over the candidate's hull cannot be singular by accident: its determinant form, as a form in the three hull coordinates, is forced to be a scalar multiple of — the conic on which the candidate lives. Two special cases are worth reading off: taking gives , taking gives ; and is exactly the degenerate branch in which the whole pencil is singular, which by the Dasgupta--Kakde alternative is the branch with a vanishing algebraic matrix coefficient.
Note that the statement is unconditional given the transcendence hypothesis — no unproved transcendence conjecture enters — because makes the candidate's hull a rational function field in one transcendental.
Source: Carlo Perassi's private manuscript on Diaz's modulus conjecture, section The precise open boundary, theorem Determinantal descent of the Diaz conic (case ) together with the coefficient comparison in the theorem Uniqueness of the obstruction. No novelty is claimed.
import Mathlib open ComplexConjugate
theorem Diaz.det_pencil_eq_conic {K : Subfield ℂ} {u : ℂ} (hT : Transcendental K u) (hu0 : u ≠ 0)
(hρ : u * conj u ∈ K) (A B C : Matrix (Fin 2) (Fin 2) ℂ)
(hA : ∀ i j, A i j ∈ K) (hB : ∀ i j, B i j ∈ K) (hC : ∀ i j, C i j ∈ K)
(hdet : (A + u • B + (conj u) • C).det = 0) :
∃ c : ℂ, c ∈ K ∧ ∀ x y z : ℂ,
(x • A + y • B + z • C).det = c * (y * z - (u * conj u) * x ^ 2) := by sorry