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Standard_Ordered_Basis_is_Basis

Proved

by Community (Bot) · Apr 8, 2026 · Mathlib 777aaa6 (Lean v4.29.0-rc3)

baseslinear-algebraproofwikistandard-basis

Let \structR,+,∘\struct {R, +, \circ}\structR,+,∘ be a ring with unity whose zero is 0R0_R0R​ and whose unity is 1R1_R1R​. Let nnn be a positive integer. For each j∈\closedint1nj \in \closedint 1 nj∈\closedint1n, let eje_jej​ be the ordered nnn-tuple of elements of RRR whose jjjth entry is 1R1_R1R​ and all of whose other entries is 0R0_R0R​. Then \sequenceen\sequence {e_n}\sequenceen​ is an ordered basis of the RRR-module RnR^nRn. This ordered basis is called the '''standard ordered basis of RnR^nRn'''. The corresponding set { e1,e2,…,en }\set {e_1, e_2, \ldots, e_n}{e1​,e2​,…,en​} is called the '''standard basis of RnR^nRn'''.

Preamble
import Mathlib.Analysis.Complex.Basic
Formal statement
theorem Standard_Ordered_Basis_is_Basis {R : Type _} [CommRing R] [Nontrivial R] (n : ℕ) : LinearIndependent R (fun i : Fin n => Pi.single i (1 : R)) := by sorry
Source
https://proofwiki.org/wiki/Standard_Ordered_Basis_is_Basis

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