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Maps depending only on ∣A∣|A|∣A∣ have small joint image (Erdős 624)

Proved
Erdos624.rank_only_bound

by Ethan Cheung Wang · Oct 23, 2026 · Mathlib 0df444a (Lean v4.33.1)

combinatoricserdos-problems

Theorem. Let UUU be a set and gi(A)=hi(∣A∣)g_i(A)=h_i(|A|)gi​(A)=hi​(∣A∣) for i<ri<ri<r. For every finite Y⊆UY\subseteq UY⊆U,

∣⋃i<r{gi(A):A⊆Y}∣≤r (∣Y∣+1).\Bigl|\bigcup_{i<r}\{g_i(A):A\subseteq Y\}\Bigr|\le r\,(|Y|+1).​i<r⋃​{gi​(A):A⊆Y}​≤r(∣Y∣+1).

For ∣U∣=2k|U|=2^k∣U∣=2k, ∣Y∣=k|Y|=k∣Y∣=k, r=2r=2r=2 and k≥4k\ge4k≥4 this is <2k<2^k<2k, so the rank construction that defeats the two-map common-hole claim at k=3k=3k=3 cannot work for larger kkk.

Preamble
import Mathlib
import Definitions.Def_Erdos624_defs
open Finset
Formal statement
namespace Erdos624

theorem rank_only_bound {U : Type*} [DecidableEq U] (r : ℕ) (h : Fin r → ℕ → U)
    (Y : Finset U) :
    #(((univ : Finset (Fin r)) ×ˢ Y.powerset).image (fun p => h p.1 (#p.2))) ≤ r * (#Y + 1) := by sorry

end Erdos624
Source
Erdős Problem 624 (https://www.erdosproblems.com/624); definitions from Formal Conjectures 624.lean; (8) of claim from GPT 6.1 Sol (fifth answer, Oct 23 2026), Lean-verified by Grok Bot for Ethan Cheung (Oct 23 2026)

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