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Collision identity for two maps P(U)→U\mathcal P(U)\to UP(U)→U (Erdős 624)

Proved
Erdos624.collision_identity

by Ethan Cheung Wang · Oct 23, 2026 · Mathlib 0df444a (Lean v4.33.1)

combinatoricserdos-problems

Theorem. Let ∣U∣=n=2k|U|=n=2^k∣U∣=n=2k, g0,g1:P(U)→Ug_0,g_1:\mathcal P(U)\to Ug0​,g1​:P(U)→U, and Y⊆UY\subseteq UY⊆U with ∣Y∣=k|Y|=k∣Y∣=k. Let J(Y)={gi(A):i∈{0,1},A⊆Y}J(Y)=\{g_i(A):i\in\{0,1\},A\subseteq Y\}J(Y)={gi​(A):i∈{0,1},A⊆Y} and let C(Y)=2n−∣J(Y)∣C(Y)=2n-|J(Y)|C(Y)=2n−∣J(Y)∣ be the number of repeated evaluations among the 2n2n2n evaluations. Then

C(Y)=n+(n−∣J(Y)∣),C(Y)=n+\bigl(n-|J(Y)|\bigr),C(Y)=n+(n−∣J(Y)∣),

and the two maps have a common hole on YYY if and only if C(Y)>nC(Y)>nC(Y)>n. An elementary bookkeeping identity: a two-map common hole needs more than nnn collisions, not just large separate losses.

Formalization Note. U=Fin (2k)U=\mathrm{Fin}\,(2^k)U=Fin(2k); evaluations indexed by Fin 2×P(Y)\mathrm{Fin}\,2\times\mathcal P(Y)Fin2×P(Y).

Preamble
import Mathlib
import Definitions.Def_Erdos624_defs
open Finset
Formal statement
namespace Erdos624

theorem collision_identity (k : ℕ) (g : Fin 2 → Finset (Fin (2 ^ k)) → Fin (2 ^ k))
    (Y : Finset (Fin (2 ^ k))) (hY : #Y = k) :
    #((univ : Finset (Fin 2)) ×ˢ Y.powerset) -
        #(((univ : Finset (Fin 2)) ×ˢ Y.powerset).image (fun p => g p.1 p.2)) =
      2 ^ k + (2 ^ k - #(((univ : Finset (Fin 2)) ×ˢ Y.powerset).image (fun p => g p.1 p.2))) ∧
    ((∃ u, ∀ i, ∀ A ⊆ Y, g i A ≠ u) ↔
      2 ^ k < #((univ : Finset (Fin 2)) ×ˢ Y.powerset) -
        #(((univ : Finset (Fin 2)) ×ˢ Y.powerset).image (fun p => g p.1 p.2))) := by sorry

end Erdos624
Source
Erdős Problem 624 (https://www.erdosproblems.com/624); definitions from Formal Conjectures 624.lean; (1) of claim from GPT 6.1 Sol (fifth answer, Oct 23 2026), Lean-verified by Grok Bot for Ethan Cheung (Oct 23 2026)

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