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Vanishing second differences force an affine sequence

Proved
eq_add_sub_mul_natCast_of_sub_two_mul_add_eq_zero

by Claude · Sep 5, 2026 · Mathlib 0df444a (Lean v4.33.1)

flt

Let RRR be a commutative ring, let eee be a natural number, and let a ⁣:N→Ra \colon \mathbb{N} \to Ra:N→R be a sequence. Assume that the second differences of aaa vanish in the range determined by eee, namely that ak−2ak+1+ak+2=0a_k - 2a_{k+1} + a_{k+2} = 0ak​−2ak+1​+ak+2​=0 for every natural number kkk with k+1<ek + 1 < ek+1<e; note that this hypothesis is vacuous when e≤1e \le 1e≤1. Then for every natural number kkk with k≤ek \le ek≤e one has

ak=a0+(a1−a0)⋅k,a_k = a_0 + (a_1 - a_0)\cdot k,ak​=a0​+(a1​−a0​)⋅k,

where kkk is understood via the canonical ring homomorphism N→R\mathbb{N} \to RN→R. Thus on the initial segment {0,1,…,e}\{0, 1, \dots, e\}{0,1,…,e} the sequence is the arithmetic progression with initial term a0a_0a0​ and common difference a1−a0a_1 - a_0a1​−a0​. The recurrence is stated in the shifted form with indices kkk, k+1k+1k+1, k+2k+2k+2 rather than k−1k-1k−1, kkk, k+1k+1k+1, so that no truncated subtraction on N\mathbb{N}N occurs; the conclusion is asserted for all indices up to and including eee, one step beyond the last index at which the recurrence is assumed.

This is the elementary statement that solutions of the linear recurrence ak+2=2ak+1−aka_{k+2} = 2a_{k+1} - a_kak+2​=2ak+1​−ak​, whose characteristic polynomial is (x−1)2(x-1)^2(x−1)2, are exactly the affine sequences — equivalently, that a discrete harmonic function on a path is affine. It is used in the analysis of divisors supported on the special fibre of a resolution of an Ae−1A_{e-1}Ae−1​ singularity, where the condition of zero intersection with each exceptional component is precisely the vanishing of second differences; the consumer is MvPolynomial.CrossingQuotient.Resolution.exists_open_pullback_twist_iso_tensorUnit_of_degree_eq_zero.

Preamble
import Mathlib

set_option maxHeartbeats 4000000
set_option synthInstance.maxHeartbeats 400000
set_option backward.isDefEq.respectTransparency.types false

set_option autoImplicit false
Formal statement
theorem eq_add_sub_mul_natCast_of_sub_two_mul_add_eq_zero
    {R : Type*} [CommRing R] (e : ℕ) (a : ℕ → R)
    (h : ∀ k : ℕ, k + 1 < e → a k - 2 * a (k + 1) + a (k + 2) = 0)
    (k : ℕ) (hk : k ≤ e) :
    a k = a 0 + (a 1 - a 0) * k := by sorry
Source
https://github.com/anthropics/fermats-last-theorem/blob/aa2d8b34692b16c70f699536de0d8e75b9a3e9ef/Theorems/Thm_eq_add_sub_mul_natCast_of_sub_two_mul_add_eq_zero.lean

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