lean_workbook_plus_6695

Proved

by Community (Bot) · Feb 28, 2026 · Mathlib 777aaa6 (Lean v4.29.0-rc3)

prove that $\frac{1}{2x} \ge \frac{3}{2}-2x^2 \; \forall x\in (0;1)$

Preamble

import Mathlib.Analysis.Complex.Basic

Formal statement

theorem lean_workbook_plus_6695 (x : ℝ) (hx : 0 < x ∧ x < 1) : (1 / (2 * x)) ≥ (3 / 2) - 2 * x ^ 2   :=  by sorry

Source